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Leni [432]
2 years ago
9

How is sound is different from music how loundness od sound mention some ways to reduce

Physics
1 answer:
kondor19780726 [428]2 years ago
3 0

not too sure on this one maybe to locate objects under water, to diagnose problems, to treat medical ailments

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Suppose multiple stations are connected in wired network where CSMA/CD implemented. Among them, station A wants to communicate w
anastassius [24]

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bro i think ur from the uni of arid agriculture rawalpindi and today is your networking paper

Explanation:

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3 years ago
What are the laws of Physics​
uranmaximum [27]

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thermodynamics

Explanation:

The laws of thermodynamics define a group of physical quantities, such as temperature, energy, and entropy, that characterize thermodynamic systems in thermodynamic equilibrium.

8 0
2 years ago
Increasing the concentration of greenhouse gases in Earth's atmosphere decreases the transparency of the atmosphere to infrared
kondaur [170]

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Decreases the transparency of the atmosphere to infrared light.

Explanation:

When a large amount of green-house gases are present in the atmosphere, the layer of these gases become opaque to infrared radiation and radiation from the sun get trapped into these gases molecules. These excited molecules radiate this energy into our own atmosphere and that why the temperature of Earth is rising due to the Green-House effect.

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3 years ago
Three common elements that can reorient their electrons into magnetic domains and become magnetic are iron, nickel, and ________
ohaa [14]

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Cobalt

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8 0
2 years ago
Observe the given figure and find the the gravitational force between m1 and m2.​
Leno4ka [110]

Answer:

The gravitational force between m₁ and m₂, is approximately 1.06789 × 10⁻⁶ N

Explanation:

The details of the given masses having gravitational attractive force between them are;

m₁ = 20 kg, r₁ = 10 cm = 0.1 m, m₂ = 50 kg, and r₂ = 15 cm = 0.15 m

The gravitational force between m₁ and m₂ is given by Newton's Law of gravitation as follows;

F =G \cdot \dfrac{m_{1} \cdot m_{2}}{r^{2}}

Where;

F = The gravitational force between m₁ and m₂

G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²

r₂ = 0.1 m + 0.15 m = 0.25 m

Therefore, we have;

F = 6.67430 \times 10^{-11} \ N \cdot m^2/kg \times \dfrac{20 \ kg\times 50 \ kg}{(0.1 \ m+ 0.15 \ m)^{2}} \approx 1.06789 \times 10^{-6} \ N

The gravitational force between m₁ and m₂, F ≈ 1.06789 × 10⁻⁶ N

8 0
2 years ago
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