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marysya [2.9K]
3 years ago
5

*PLZ HELP ASAP* Saturn and Jupiter both complete one rotation in about____hours.

Physics
2 answers:
Debora [2.8K]3 years ago
8 0

Answer:

10

Explanation: Earth takes 24 hours to complete one spin, and Mars takes 25 hours. The gas giants rotate really fast. Jupiter takes just 10 hours to complete one rotation. Saturn takes 11 hours, Uranus takes 17 hours, and Neptune takes 16 hours.

grigory [225]3 years ago
6 0

Answer:

10 hours

Explanation:

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Two objects attract each other gravitationally with a force of 2.5 x 10^-10N when they are 0.25 m apart. Their total mass is 4.0
In-s [12.5K]

Answer:

M = 3.9406 kg and m = 0.0594 kg

Explanation:

The gravitational force between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distance that separates them. Mathematically it is expressed as follows:

Fg = (G×M×m)/r²    Formula (1)

Where:

Fg is the gravitational force (N)

G is the universal gravitation constant, G = 6.67 × 10⁻¹¹ (N×m²)/kg²

M and m are the masses of the bodies that interact  (kg).

r is the distance that separates them (m).

Known Data

Fg = 2.5 × 10⁻¹⁰ N

r = 0.25 m

G = 6.67 × 10⁻¹¹ (N×m²)/kg²

Problem development

We propose 2 equations

M + m = 4kg

M = 4 - m equation (1)

We replace in formula (1)

2.5 × 10⁻¹⁰ = (6.67 × 10⁻¹¹ × M × m)/(0.25)²

2.5 × 10⁻¹⁰ × (0.25)² = (6.67 × 10⁻¹¹ × M × m)

(2.5 × 10⁻¹⁰ × (0.25)²)/(6.67 × 10⁻¹¹) = M × m

M × m = 0.234 equation (2)

We replace M = 4 - m in equation (2)

(4 - m) × m = 0.234

4m - m² = 0.234

m² - 4m + 0.234 = 0 (quadratic equation)

We apply the formula for the quadratic equation and obtain 2 values for m that meet the conditions:

m = 3.9406 kg or m =  0.0594 kg

We replace m in equation (1)

M = 4 - 3.9406 = 0.0594 kg or M = 4 - 0.0594 = 3.9406

To meet the condition that M + m must give 4 kg, one mass must be equal 3.9406 and the other must equal 0.0594, then:

M = 3.9406 kg and m = 0.0594 kg

6 0
4 years ago
Solve the problem. Unless stated otherwise, assume that the projectile flight is ideal, that the launch angle is measured from t
kirill115 [55]

Answer:

d = 185.26 meters

Explanation:

It is given that,

Launching angle of the projectile, \theta=26^{\circ}

Initial speed of the projectile, u = 48 m/s

Let at distance d the projectile hits the ground from the launch point. It is equal to range of the projectile. Its formula is given by :

d=\dfrac{u^2\ sin2\theta}{g}

Substituting all the values in above formula. So, we get :

d=\dfrac{(48)^2\ sin2(26)}{9.8}

d = 185.26 meters

So, the distance between the launch point and the point where it hits is 185.26 meters. Hence, this is the required solution.

3 0
3 years ago
What is the average velocity of a rocket that travels 15 m in 0.25 seconds?​
Brrunno [24]

Answer:

<em><u>60 m/s</u></em>

Explanation:

Average Speed = Distance/ Time

= 15/0.25 = 60m/s

5 0
4 years ago
How is the current controlled for a given voltage
Leni [432]

Answer:

The current can be controlled by modifying the resistance value

Explanation:

The current can be controlled by modifying the resistance value, usually a variable resistance device called potentiometer is used. This can be observed mathematically using the ohm law which is defined as voltage equal to the current product by resistance.

V = I*R

where:

I = current [amp]

R = resistance [ohm]

V = voltage [volt]

We can see that if we reduce the resistance the current will be increased

I = v / R

And if we amplify the resistance (R) the current will be diminished

6 0
4 years ago
Now it's your turn
eduard

Answer:

The average force the golf club exerts on the ball is 600 N

Explanation:

Newton's second law of motion states that force, F, is directly proportional to the rate of change of momentum produced

F = m× (v₂ - v₁)/(Δt)

The given parameters of the motion of the ball are;

The mass of the ball, m = 45 g = 0.045 kg

The initial velocity of the ball, v₁ = 0 m/s

The speed with which the ball was hit by the golfer, v₂ = 40 m/s

The duration of contact between the golf club and the ball, Δt = 3 ms = 0.003 seconds (s)

By Newton's law of motion, the average force, 'F', which the golf club exerts on the ball is therefore, given as follows;

F = 0.045 kg × (40 m/s - 0 m/s)/(0.003 s) = 600 N

The average force the golf club exerts on the ball = F = 600 N.

5 0
3 years ago
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