Troposphere.
Hope it helps!
Answer:
20 chromosomes
Explanation:
Mitosis is a kind of cell division that results in daughter cells with same number of chromosomes as the parent cell. It involves stages including Prophase, Metaphase, Anaphase and Telophase. In prophase, the Chromatin condenses into Chromosomes.
In Anaphase stage, the 10 chromosomes as mentioned in the question divides into opposite poles of the cell. One individual chromosome contains two sister chromatids, which actually separates in the Anaphase stage. Hence, at the end of the Anaphase stage, there will be 10 chromatids each at opposite poles of the cell. Each chromatid at this stage is considered a chromosome.
Hence, a cell with 10 chromosomes will contain 20 chromosomes (10+10 chromatids on each pole) in the Anaphase stage just before the cell divides into two in a process called CYTOKINESIS.
Plate tectonics and the ocean floor. ... Where plates are pulled away (diverge) from each other molten magma flows upward between the plates forming mid-ocean ridges, underwater volcanoes, hydrothermal vents, and new ocean floor crust. The Mid-Atlantic Ridge, is an example of this type of plate boundary.
Answer:
C) A, B, and C
Explanation:
The amount of Earth's surface water that is not located in the oceans is the addition of A, B, and C in the pie chart.
About 71% of the Earth's surface is covered by water. The ocean has been reported to hold about 97% of all the water on earth while water present in air, rivers, lakes, glaciers and biological systems constitute the remaining percentage.
<em>From the chart, D can be said to represent the amount of earth's surface water held by oceans while the rest (A, B, and C) can be said to be the amount of Earth's surface water that is not located in the oceans.</em>
The correct option is C.
Multiply 5730 years by 2 since two half-lives have gone by for carbon.
<u>Explanation</u>:
The half-life of a radioactive isotope depicts the measure of time that it takes half of the isotope in an example decay. On account of radiocarbon dating, the half-existence of carbon 14 is 5,730 years
The half-life of carbon-14 is 5730 years.
In this manner, after
1 half-life there is 50 % = 1/2 of the first amount left.
2 half-lives there is 25 % = 1/4 of the first amount left.
25% is two half-lives.
Every 50% of life requires 5730 years.
So two half-lives require 2 × 5730
