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goblinko [34]
2 years ago
8

Help me out asap!!!!

Mathematics
1 answer:
attashe74 [19]2 years ago
6 0

Answer:

anglePUM = 3° , PM = 5, UM = √75

Step-by-step explanation:

anglePUM = 180 - 60 - 90 = 30° (∠sum of Δ)

cos60 = PM/10

PM = 10cos60 = 5

sin60 = UM/10

UM = 10sin60 = √75

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The curved surface area of a right circular cylinder of height 14 cm is 88 cm². ​
Slav-nsk [51]

Answer:

The diameter of the base of the cylinder is 2 cm.

Step-by-step explanation:

<u>GIVEN</u> :

As per given question we have provided that :

  • ➣ Height of cylinder = 14 cm
  • ➣ Curved surface area = 88 cm²

\begin{gathered}\end{gathered}

<u>TO</u><u> </u><u>FIND</u> :

in the provided question we need to find :

  • ➠ Radius of cylinder
  • ➠ Diameter of cylinder

\begin{gathered}\end{gathered}

<u>USING</u><u> </u><u>FORMULAS</u> :

\star{\underline{\boxed{\sf{\purple{Csa = 2 \pi rh}}}}}

\star{\underline{\boxed{\sf{\purple{d = 2r}}}}}

  • ➛ Csa = Curved surface area
  • ➛ π = 22/7
  • ➛ r = radius
  • ➛ h = height
  • ➛ d = diameter

\begin{gathered}\end{gathered}

<u>SOLUTION</u> :

Firstly, finding the radius of cylinder by substituting the values in the formula :

\begin{gathered} \qquad{\longrightarrow{\sf{Csa = 2 \pi rh}}} \\  \\ \qquad{\longrightarrow{\sf{88 = 2 \times \dfrac{22}{7} \times r \times 14}}}  \\  \\ \qquad{\longrightarrow{\sf{88 =\dfrac{44}{7} \times r \times 14}}} \\  \\ \qquad{\longrightarrow{\sf{88 =\dfrac{44}{\cancel{7}}\times r \times  \cancel{ 14}}}}  \\  \\  \qquad{\longrightarrow{\sf{88 =44 \times r \times 2}}} \\  \\ \qquad{\longrightarrow{\sf{88 =88 \times r}}} \\  \\ \qquad{\longrightarrow{\sf{r =  \frac{88}{88}}}} \\  \\ \qquad{\longrightarrow{\underline{\underline{\sf{\pink{r = 1 \: cm}}}}}} \end{gathered}

Hence, the radius of cylinder is 1 cm.

———————————————————————

Now, finding the diameter of cylinder by substituting the values in the formula :

\begin{gathered} \qquad{\longrightarrow{\sf{d = 2r}}} \\  \\  \qquad{\longrightarrow{\sf{d = 2 \times 1}}} \\  \\ \qquad{\longrightarrow{\underline{\underline{\sf{\red{r = 2 \: cm}}}}}}\end{gathered}

Hence, the diameter of the base of the cylinder is 2 cm.

\rule{300}{2.5}

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