g Suppose we want to know what proportion p of students in a large university have studied calculus in high school. At least how
many students should we include in a sample if we want to estimate p with an error bound of 0.03 (at most) with 95% confidence
1 answer:
Answer:
1067
Step-by-step explanation:
Given that:
Error (E) = 0.03
Confidence interval = 95% = 0.95
Sample size (n) = ((Zα/2) / Error)^2 * p(1 - p)
Since no assumption is given ; p = 0.5
α = 0.95
Z(1-α/2) = 1.96
(1.96 / 0.03)^2 * 0.5(1 - 0.5)
(65.333333)^2 * 0.5(0.5)
4268.4444 * 0.25
= 1067.1111
n = 1067
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It looks to be the correct answer because for the one above you can't simplify 27 by 5.
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