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Lana71 [14]
3 years ago
12

Jaden sells a painting for 10 times the original price he sells a painting for $45.50 what was the original price of this painti

ng
Mathematics
2 answers:
Ymorist [56]3 years ago
6 0
x-\ original\ price\\\\
10x=45,50\ \ \ \ | divide\ by\ 10\\\\
x=4,550\$\\\\
Original\ price\ is\ 4,550\$.
Lelechka [254]3 years ago
6 0
The orginal problem was x times 10, so to find the original you'd have to do it backwards and divide by 10:

45.50/10 = 4.55$

Hope this helps!
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A segment has endpoints at (-2,3) and (7,9), How long is the segment?
trasher [3.6K]
l=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}=\sqrt{(7-(-2))^2+(9-3)^2}=\sqrt{9^2+6^2}\\=\sqrt{81+36}=\sqrt{117}=10.82 \ units
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3 years ago
The length of a pool table is 71 feet and the width is 36 feet. Find the area of the surface of the pool table by multiplying th
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Answer:

2556 feet squared

Step-by-step explanation:

Area is calculated by multiplying length times width. 71x36=2556

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3 years ago
Which ordered pairs are solutions to the inequality 2y−x≤−6 ?
jeka94
(0,-3) or the option 2 hope this helps
3 0
3 years ago
Read 2 more answers
Given the functionf ( x ) = x^2 + 7 x + 10/ x^2 + 9 x + 20
vladimir1956 [14]

<em>x = -4 is a vertical asymptote for the function.</em>

<h2>Explanation:</h2>

The graph of y=f(x) is a vertical has an asymptote at x=a if at least one of the following statements is true:

1) \ \underset{x\rightarrow a^{-}}{lim}f(x)=\infty\\ \\ 2) \ \underset{x\rightarrow a^{-}}{lim}f(x)=-\infty \\ \\ 3) \ \underset{x\rightarrow a^{+}}{lim}f(x)=\infty \\ \\ 4) \ \underset{x\rightarrow a^{+}}{lim}f(x)=\infty

The function is:

f(x)=\frac{x^2+7x+10}{x^2+9x+20}

First of all, let't factor out:

f(x)=\frac{x^2+5x+2x+10}{x^2+5x+4x+20} \\ \\ f(x)=\frac{x(x+5)+2(x+5)}{x(x+5)+4(x+5)} \\ \\ f(x)=\frac{(x+5)(x+2)}{(x+5)(x+4)} \\ \\ f(x)=\frac{(x+2)}{(x+4)}, \ x\neq  5

From here:

\bullet \ When \ x \ approaches \ -4 \ on \ the \ right: \\ \\ \underset{x\rightarrow -4^{+}}{lim}\frac{(x+2)}{(x+4)}=? \\ \\ \underset{x\rightarrow -4^{+}}{lim}\frac{(-4^{+}+2)}{(-4^{+}+4)} \\ \\ \\ The \ numerator \ is \ negative \ and \ the \ denominator \\ is \ a \ small \ positive \ number. \ So: \\ \\ \underset{x\rightarrow -4^{+}}{lim}\frac{(x+2)}{(x+4)}=-\infty

\bullet \ When \ x \ approaches \ -4 \ on \ the \ left: \\ \\ \underset{x\rightarrow -4^{-}}{lim}\frac{(x+2)}{(x+4)}=? \\ \\ \underset{x\rightarrow -4^{-}}{lim}\frac{(-4^{-}+2)}{(-4^{-}+4)} \\ \\ \\ The \ numerator \ is \ a \ negative \ and \ the \ denominator \\ is \ a \ small \ negative \ number \ too. \ So: \\ \\ \underset{x\rightarrow -4^{-}}{lim}\frac{(x+2)}{(x+4)}=+\infty

Accordingly:

x=-4 \ is \ a \ vertical \ asymptote \ for \\ \\ f(x)=\frac{x^2+5x+2x+10}{x^2+5x+4x+20}

<h2>Learn more:</h2>

Vertical and horizontal asymptotes: brainly.com/question/10254973

#LearnWithBrainly

5 0
3 years ago
What's the vertex and is it a max or min
MrRa [10]
A vertex can be the max or min. The vertex is the highest point or lowest point of a function.
5 0
3 years ago
Read 2 more answers
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