The situation can be modeled by a geometric sequence with an initial term of 284. The student population will be 104% of the prior year, so the common ratio is 1.04.
Let \displaystyle PP be the student population and \displaystyle nn be the number of years after 2013. Using the explicit formula for a geometric sequence we get
{P}_{n} =284\cdot {1.04}^{n}P
n
=284⋅1.04
n
We can find the number of years since 2013 by subtracting.
\displaystyle 2020 - 2013=72020−2013=7
We are looking for the population after 7 years. We can substitute 7 for \displaystyle nn to estimate the population in 2020.
\displaystyle {P}_{7}=284\cdot {1.04}^{7}\approx 374P
7
=284⋅1.04
7
≈374
The student population will be about 374 in 2020.
Answer:
6.34013 quarts
Step-by-step explanation:
i looked it up
Answer:
-44
Step-by-step explanation:
first take -2 to the fifth power (-32) , after that take -2 to the second power (4) and then take -2 to the third power (-8). Subtract -32 and 4, then add -8 and you get your answer.
The chance of you selecting one randomly is 4/56, which simplifies to 1/14.
The answer is 481.6, because 56% = 0.56, so just multiply 860 by 0.56 and u get 481.6
