All categories

2 years ago

After how many hours was the temperature at 20 degrees F? Enter only the number.

Mathematics

1 answer:

enyata [817]2 years ago

5 0

Answer:

Step-by-step explanation:

You might be interested in

Locating Zeros of Polynomial Function:<br>Approximate the real zeros to the nearest tenth

solmaris [256]

we are given

$f(x)=2x^4-x^3+x-2$

we can check each options

option-A:

-1,1

we can plug x=-1 and x=1 and check whethet f(x)=0

At x=-1:

$f(-1)=2(-1)^4-(-1)^3+(-1)-2$

$f(-1)=0$

At x=1:

$f(1)=2(1)^4-(1)^3+(1)-2$

$f(1)=0$

so, this is TRUE

option-B:

0,1

we can plug x=0 and x=1 and check whethet f(x)=0

At x=0:

$f(0)=2(0)^4-(0)^3+(0)-2$

$f(0)=-2$

At x=1:

$f(1)=2(1)^4-(1)^3+(1)-2$

$f(1)=0$

so, this is FALSE

option-C:

-2,-1

we can plug x=-2 and x=-1 and check whethet f(x)=0

At x=-2:

$f(-2)=2(-2)^4-(-2)^3+(-2)-2$

$f(-2)=36$

At x=-1:

$f(-1)=2(-1)^4-(-1)^3+(-1)-2$

$f(-1)=0$

so, this is FALSE

option-D:

-1,0

we can plug x=-1 and x=0 and check whethet f(x)=0

At x=-1:

$f(-1)=2(-1)^4-(-1)^3+(-1)-2$

$f(-1)=0$

At x=0:

$f(0)=2(0)^4-(0)^3+(0)-2$

$f(0)=-2$

so, this is FALSE

5 0

3 years ago

This needs to be simplified and clearly i don’t know the answer <br><br> -23b^4+(-7b^4)

vladimir2022 [97]

$\text{Hello there!}\\ \\ \text{In this question, you need to simplify by adding like terms}\\ \\\text{Both terms are}\,\,b^4,\,\,\text{in which you can combine them}\\\\-23b^4+(-7b^4)\\\\\text{Add them}\\\\-30b^4\\\\\large\boxed{-30b^4}$

5 0

2 years ago

Read 2 more answers

A piece of tile is 4 1/2 inches long and 3 1/4 inches wide. What is the area of the tile? A. 7 3/4 square inches B. 12 square in

mario62 [17]

First change the 4 $\frac{1}{2}$ to 4 $\frac{2}{4}$ .
Then multiply 4 $\frac{2}{4}$ and 3 $\frac{1}{4}$
The answer would be D) or 14 $\frac{5}{8}$ in².

8 0

3 years ago

Sixty three thousandths in standard form

Hunter-Best [27]

Answer:

sounds like .063 to me

3 0

2 years ago

Scott wants to tip his taxi driver 20%. if his commute costs $15 what is the total cost

Vlad [161]

The total cost is $18

8 0

3 years ago