To help solve the trigonometric inequality 2sin^2(x)+. cos(2x)-2<-1, Tracey successfully graphed the equations y=2sin^2(x) +c
os(2x)-2 and y=-1 with her graphing calculator. Which of the following statements is true about the inequality? a. There is no solution because even though you cannot see it, the graph of the equation y=2sin^2(x) +cos(2x) -2 is above the graph of the equation y=-1 for all values of x.
b. There is no solution because the graph of the equation y=2sin^2(x) +2cos(x)-2 is the same as the graph of the equation y=-1, so y=2sin^2(x) +2cos(x)-2 is never below y=-1.
c.There are an infinite number of solutions because even though you cannot see it, the graph of the equation y=2sin^2(x) +2cos(x)-2 is below the graph of the equation y=-1 for all values of x.
d.There are an infinite number of solutions because the graph of the equation y=2sin^2(x) +2cos(x)-2 is the same as the graph of the equation y=-1, so y=2sin^2(x) +2cos(x)-2 is never below y=-1.
Step-by-step explanation: I took the quiz and got it right
Also, if you graph the equations on a graphing calculator, the lines are right on top of each other, so the first equation can't be less than -1, so no solutions
