To help solve the trigonometric inequality 2sin^2(x)+. cos(2x)-2<-1, Tracey successfully graphed the equations y=2sin^2(x) +c
2 answers:
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Answer:
Answers are below!
Step-by-step explanation:
(2 + g) (8)
= (2 + g) (8)
Add a 8 after the 2, and flip.
= (2)(8) + (g)(8)
= 16 + 8g
= 8g + 16
= (4) (8 + -5g)
Add another 4, then flip.
= (4) (8) + (4) (-5g)
= 32 − 20g
= - 20g + 32
−7 (5-n)
= (−7) (5 + -n)
Add another 7, then flip.
= (−7) (5) + (-7) (-n)
= −35 + 7n
= 7n - 35
Use the distributive property.
a (b + c) = ab + ac
a = 8
b = 2m
c = 1
= 8 × 2m + 8 × 1
Simplify, you get 16m + 8.
Use the distributive property.
a (b + c) = ab + ac
a = 6x
b = y
c = z
= 6xy - 6xz is the answer.
Apply minus plus rules.
Multiply the numbers.
3 x 2 = 6
The area of D is given by:
The average value of f over D is given by:
![\frac{1}{ \frac{343}{3} } \int\limits^7_0 \int\limits^{x^2}_0 {4x\sin(y)} \, dydx = -\frac{3}{343} \int\limits^7_0 {4x\cos(x^2)} \, dx \\ \\ =-\frac{3}{343} \int\limits^{49}_0 {2\cos(t)} \, dt=-\frac{6}{343} \left[\sin(t)\right]_0^{49} \, dt=-\frac{6}{343}\sin49](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B%20%5Cfrac%7B343%7D%7B3%7D%20%7D%20%20%5Cint%5Climits%5E7_0%20%20%5Cint%5Climits%5E%7Bx%5E2%7D_0%20%7B4x%5Csin%28y%29%7D%20%5C%2C%20dydx%20%20%3D%20-%5Cfrac%7B3%7D%7B343%7D%20%20%5Cint%5Climits%5E7_0%20%7B4x%5Ccos%28x%5E2%29%7D%20%5C%2C%20dx%20%20%5C%5C%20%20%5C%5C%20%3D-%5Cfrac%7B3%7D%7B343%7D%20%5Cint%5Climits%5E%7B49%7D_0%20%7B2%5Ccos%28t%29%7D%20%5C%2C%20dt%3D-%5Cfrac%7B6%7D%7B343%7D%20%5Cleft%5B%5Csin%28t%29%5Cright%5D_0%5E%7B49%7D%20%5C%2C%20dt%3D-%5Cfrac%7B6%7D%7B343%7D%5Csin49)
The average value of f over D is given by: