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3 years ago

One-third of a number added to itself equals 3 times the difference of the number and seven.

Mathematics

1 answer:

olya-2409 [2.1K]3 years ago

3 0

Answer:

Step-by-step explanation:

Do this step by step.

Let the number = x

1/3 of a number = 1/3 x

Added to itself 1/3x + x

3*(x - 7)

So the equation is

1/3x + x = 3(x - 7) Remove the brackets. Collect 1/3x and x

4/3 x = 3x - 21 Multiply both sides by 3.

4x = 3*(3x - 21) Remove the brackets again

4x = 9x - 63 Subtract 9x from both sides

-5x = -63 Divide by -5

x = -63/-5

x = 12.6

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Suppose the half-life of a material is 10 days. You have one 1 kg of the material today. How much of the material would you have

boyakko [2]

Answer:

0.50 kg of the material would be left after 10 days.

0.25 kg of the material would be left after 20 days.

Step-by-step explanation:

We have been given that the half-life of a material is 10 days. You have one 1 kg of the material today. We are asked to find the amount of material left after 10 days and 20 days, respectively.

We will use half life formula.

$A=a\cdot(\frac{1}{2})^{\frac{t}{h}}$ , where,

A = Amount left after t units of time,

a = Initial amount,

t = Time,

h = Half-life.

$A=1\text{ kg}\cdot(\frac{1}{2})^{\frac{10}{10}}$

$A=1\text{ kg}\cdot(\frac{1}{2})^{1}$

$A=1\text{ kg}\cdot\frac{1}{2}$

$A=0.5\text{ kg}$

Therefore, amount of the material left after 10 days would be 0.5 kg.

$A=1\text{ kg}\cdot(\frac{1}{2})^{\frac{20}{10}}$

$A=1\text{ kg}\cdot(\frac{1}{2})^{2}$

$A=1\text{ kg}\cdot\frac{1^2}{2^2}$

$A=1\text{ kg}\cdot\frac{1}{4}$

$A=0.25\text{ kg}$

Therefore, amount of the material left after 20 days would be 0.25 kg.

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3 years ago

With this diagram, what could be the values of c and d?

Sedaia [141]

Answer:

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Step-by-step explanation:

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3 years ago

Why is 2+2=4?????????

eduard

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3 years ago

Dddddddddddddddddddddddd

Ierofanga [76]

Answer:

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Step-by-step explanation:

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Read 2 more answers

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alukav5142 [94]

Answer:

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Step-by-step explanation:

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3 years ago