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iogann1982 [59]

2 years ago

13

The distance of one light-year is approximately 9,500,000,000,000 kilometers. What is this distance in scientific notation?

2 answers:

zhenek [66]2 years ago

7 0

Answer:

9.5*10^12 km

Step-by-step explanation:

uranmaximum [27]2 years ago

3 0

What the first person said ^^^^^

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What angle is congruent to ∠C?

Romashka [77]

Step-by-step explanation:

Order of congruence does not matter. For any angles A,B, and C , if ∠A≅∠B and ∠B≅∠C , then ∠A≅∠C . If two angles are both congruent to a third angle, then the first two angles are also congruent.

7 0

2 years ago

Help please ASAP !!!

Arisa [49]

For this case we have that by definition of trigonometric relations of rectangular triangles, that the sine of an angle is given by the opposite leg to the angle on the hypotenuse of the triangle. So:

$Sin (45) = \frac {leg} {h}$

Where h is the hypotenuse.

$\frac {\sqrt {2}} {2} = \frac {leg} {h}$

We cleared h:

$h = \frac {2leg} {\sqrt {2}}$

We rationalize:

$h = \frac {2leg} {\sqrt {2}} * \frac {\sqrt {2}} {\sqrt {2}}\\h = \frac {2 \sqrt {2} * leg} {2}\\h = \sqrt {2} * leg$

ANswer:

Option A

3 0

3 years ago

Find the distance between these two points (5,9) and (-7,-7)

Viefleur [7K]

Answer:

20

Step-by-step explanation:

Use the distance formula:

$d = \sqrt{(x_2 - x_1)^2 + (y_2-y_1)^2}\\d = \sqrt{(-7 - 5)^2 + (-7 - 9)^2}\\d = \sqrt{(-12)^2 + (-16)^2}\\d = \sqrt{144 + 256}\\d = \sqrt{400} = 20$

8 0

3 years ago

How many terms are in the binomial expansion of (2x + 3)5? <br><br> 4<br> 5<br> 6<br> 7

KatRina [158]

One more than the degree.
Answer: 6.

3 0

3 years ago

Read 2 more answers

In the adjoining figure, XY = XZ . YQ and ZP are the bisectors of <img src="https://tex.z-dn.net/?f=%20%5Cangle" id="TexFormula1

svetlana [45]

Answer:

See Below.

Step-by-step explanation:

Statements: Reasons:

$1)\, XY=XZ$ Given

$2) \text{ $ m\angle Y= m\angle Z$}$ Isosceles Triangle Theorem

$\displaystyle 3) \text{ $m\angle Y=m\angle XYQ + \angle QYZ$}$ Angle Addition

$\displaystyle 4)\text{ $YQ$ bisects $\angle XYZ$}$ Given

$5) \text{ $m\angle XYQ=m\angle QYZ$}$ Definition of Bisector

$\displaystyle 6)\text{ $m\angle Y=2m\angle QYZ$}$ Substitution

$7)\text{ $m\angle Z=m\angle XZP+m\angle PZY$}$ Angle Addition

$8)\text{ $ZP$ bisects $\angle XZY$}$ Given

$\displaystyle 9) \text{ $m\angle XZP=m\angle PZY$ }$ Definition of Bisector

$\displaystyle 10) \text{ $ m\angle Z = 2m\angle PZY $}$ Substitution

$11)\text{ } 2m\angle QYZ=2m\angle PZY$ Substitution

$12)\text{ }m\angle QYZ=m\angle PZY$ Division Property of Equality

$13)\text{ } YZ=YZ$ Reflexive Property

$14)\text{ } \Delta YZP\cong\Delta ZYQ$ Angle-Side-Angle Congruence*

$15)\text{ } YQ=ZP$ CPCTC

*For clarification:

∠Y = ∠Z

YZ = YZ (or ZY)

∠PZY = ∠QYZ

So, Angle-Side-Angle Congruence:

ΔYZP is congruent to ΔZYQ

5 0

3 years ago

Read 2 more answers