Answer:
8N
Explanation:
Applied force - Frictional force = net force
A phase of moon with more than half sunlit portion visible on the right
An object of mass
is moving with a uniform velocity of
. The kinetic energy possessed by the object is
.
Given:
Mass of an object ![$=10 \mathrm{~kg}$](https://tex.z-dn.net/?f=%24%3D10%20%5Cmathrm%7B~kg%7D%24)
Velocity ![$=4 \mathrm{~ms}^{-1}$](https://tex.z-dn.net/?f=%24%3D4%20%5Cmathrm%7B~ms%7D%5E%7B-1%7D%24)
Kinetic Energy
Mass of Object ![$\times(\text { Velocity })^{2}$](https://tex.z-dn.net/?f=%24%5Ctimes%28%5Ctext%20%7B%20Velocity%20%7D%29%5E%7B2%7D%24)
Kinetic Energy ![$=1 / 2 \times 10 \times 4 \times 4$](https://tex.z-dn.net/?f=%24%3D1%20%2F%202%20%5Ctimes%2010%20%5Ctimes%204%20%5Ctimes%204%24)
Kinetic Energy ![$=\underline{80 \mathbf{J}}$](https://tex.z-dn.net/?f=%24%3D%5Cunderline%7B80%20%5Cmathbf%7BJ%7D%7D%24)
What is Kinetic Energy?
- In physics, an object's kinetic energy is the energy it has as a result of its motion.
- It is defined as the amount of work required to accelerate a body of a given mass from rest to a certain velocity.
- The body retains its kinetic energy after gaining it during acceleration until its speed changes.
- Kinetic energy is present in a speeding bullet, a walking human, and electromagnetic radiation such as light. The energy associated with the continual, random bouncing of atoms or molecules is another type of kinetic energy.
Learn more about kinetic energy brainly.com/question/12669551
#SPJ9
Answer:
The electrical force between the given charges remains the same.
Explanation:
The expression for the electrical force is as follows as;
![F=\frac{kq_{1}q_{2}}{R^{2}}](https://tex.z-dn.net/?f=F%3D%5Cfrac%7Bkq_%7B1%7Dq_%7B2%7D%7D%7BR%5E%7B2%7D%7D)
Here, k is the constant,
are the charges, F is the electrical force and R is the distance between the charges.
It is given in the problem that the magnitudes of the charges and the magnitudes of the separation between the charges are doubled.
Then, the expression of the electrical force becomes as;
![F'=\frac{k(2q_{1})(2q_{2})}{(2R)^{2}}](https://tex.z-dn.net/?f=F%27%3D%5Cfrac%7Bk%282q_%7B1%7D%29%282q_%7B2%7D%29%7D%7B%282R%29%5E%7B2%7D%7D)
![F'=\frac{k4q_{1}q_{2}}{4R^{2}}](https://tex.z-dn.net/?f=F%27%3D%5Cfrac%7Bk4q_%7B1%7Dq_%7B2%7D%7D%7B4R%5E%7B2%7D%7D)
![F'=\frac{kq_{1}q_{2}}{R^{2}}](https://tex.z-dn.net/?f=F%27%3D%5Cfrac%7Bkq_%7B1%7Dq_%7B2%7D%7D%7BR%5E%7B2%7D%7D)
![F'=F](https://tex.z-dn.net/?f=F%27%3DF)
Therefore, the electrical force between the given charges remains the same.