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baherus [9]
3 years ago
7

I NEED HELP ASAP 1.    Suppose a skydiver (mass = 75 kg) is falling toward the Earth.  When the skydiver is 100 m above the Eart

h he is moving at 60 m/s.  At this point calculate the skydiver’s……. a.    (2 pts.) Gravitational potential energy
           
b.    (2 pts.) Kinetic energy            
c.    (2 pts.) Total mechanical energy  (The sum of kinetic and potential energy)
Physics
1 answer:
ella [17]3 years ago
5 0

PE = mgh

so (75kg)(9.8m/s2)(100m) = 73,500 Joules

KE = 1/2 m * v^2

so (1/2)(75kg)(60m/s)^2 = 135,000 Joules

ME = 208,500 Joules

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it have Potential energy

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given data

Drag the pendulum to an angle 30∘

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what form of energy does it have

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30.1 N

Explanation:

Given:

W_1 = 16\:\text{N}

W_2 = 8\:\text{N}

Let's write the components of the net forces at the intersections. Note that the system is equilibrium so all the net forces are zero.

<u>Forces</u><u> </u><u>involving</u><u> </u><u>W1</u><u>:</u>

x:\:\:\:-T_1 + T_3\cos \alpha = 0\:\: \\ \text{or}\:\:T_2 = T_3\cos \alpha\:\:\:\:\:(1)

y:\:\:\:T_3\sin \alpha - W_1 = 0\:\:\: \\ \text{or}\:\:\:T_3\sin \alpha = W_1\:\:\:\:\:\:(2)

<u>Forces</u><u> </u><u>involving</u><u> </u><u>W2</u><u>:</u>

x:\:\:\:T_1\sin 53 - T_3\sin \alpha = W_2\:\:\:\:\:\:\:(3)

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