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3 years ago

Which of the following statements accurately describes work being done.

Physics

2 answers:

Vanyuwa [196]3 years ago

7 0

Answer:

Charge is moved off a capacitor

Explanation:

1) Charge is stored on a capacitor

When charge is stored on the plates of the capacitor then in that case the energy is stored in form of electric field energy between the plates of the capacitor

2) Chemical energy is stored in a battery

Here the energy is stored in form of chemical energy which will be further converted into electrical energy.

3) Charge is moved off a capacitor

When charge is moved from one plate to other plate then work is done against the electric field between the two plates

4) Electric energy is stored In a capacitor

This is the electric field energy stored between the plates of capacitor

So correct answer work work is being done is in

3) Charge is moved off a capacitor

ivolga24 [154]3 years ago

4 0

Charge is moved of a capacitor

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How do the forces in nuclear and chemical reactions differ?

kvasek [131]

B. Chemical reactions must overcome the strong nuclear force

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3 years ago

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13. Austin rode his bike 10 m/s for two minutes. How far did he travel? A. 200 meters B. 1200 meters C. 1000 meters D. 20 meters

Semmy [17]

Answer:

B. 1200

Explanation:

60 sec in one min in 2 min there will be 120 sec. 10x120=1200

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3 years ago

A small car has a head-on collision with a large truck. Which of the following statements concerning the magnitude of the averag

andrey2020 [161]

Answer:

The small car and the truck experience the same average force.

Explanation:

Here we need to remember two of Newton's laws.

The second one says that:

F = m*a

force equals mass times acceleration.

And the third one says that;

"If an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A"

From the third law, if the car experiences a force F due to the impact with the truck, then the truck experiences the same force F due to the impact.

But this seems odd, because we would expect to see the car being more affected by the impact, right?

Well, this is explained by the second law.

Suppose that the mass of the car is m, and the mass of the truck is M.

such that M > m

Then for the small car we have:

F = m*a

And for the truck:

F = M*a'

Because the force is the same for both of them, we can write:

m*a = M*a'

a = (M/m)*a'

because M > m, then M/m > 1.

This means that the acceleration that the car experiences is larger than the acceleration for the truck, and this is why we would see that the car seems more affected by the impact, regardless of the fact that both vehicles experience the same force in the impact.

6 0

3 years ago

A man does 4,475 J of work in the process of pushing his 2.50 103 kg truck from rest to a speed of v, over a distance of 26.0 m.

Tcecarenko [31]

Answer:

a) 1.89 m/s b) 172.1 N

Explanation:

Applying the work-energy theorem, if we can neglect the friction between truck and road, the total change in kinetic energy must be equal to the work done by the external forces.
This work, is just 4,475 J.
So we can write the following equation:

$\Delta K = \frac{1}{2} * m*v^{2} = 4,475 J$