As the air molecules move through the valve they have friction as they hit the walls, and its this friction that causes it to heat up.
Explanation:
The reaction forms calcium hydroxide, Ca(OH)2 and hydrogen gas (H2). The calcium metal sinks in water and after an hour or so bubbles of hydrogen are evident, stuck to the surface of the metal.
<u><em>Answer:</em></u>
2 H₂O ............> 2 H₂ + O₂
<u><em>Explanation:</em></u>
<u>To balance a chemical equation,</u> we need to make sure that the number of moles of each element on the reactants side is equal to the number of moles of that elements on the products side.
<u>For the given equation:</u>
H₂O ............> H₂ + O₂
<u>We need to make sure that:</u>
number of moles of reacting hydrogen = number of moles of produced hydrogen
number of moles of reacting oxygen = number of moles of produced oxygen
<u>1- Let's check the Oxygen:</u>
On the reactant side, we have one mole of oxygen
On the products side, we have two moles of oxygen
To balance this, we can multiply the reactants side by 2.
<u>This will give us:</u>
2 H₂O ............> H₂ + O₂
<u>2- Let's check the Hydrogen:</u>
From part 1, we reached the following equation:
2 H₂O ............> H₂ + O₂
From this equation, we can note that:
On the reactant side, we have 2*2 = 4 moles of hydrogen
On the products side, we have 2 moles of hydrogen
To balance this, we can multiply the hydrogen in the products side by 2
<u>This will give us:</u>
2 H₂O ............> 2 H₂ + O₂
<u>3- Let's check:</u>
The equation we reached in part 2 is:
2 H₂O ............> 2 H₂ + O₂
Checking this equation, we can find that:
We have 2*2 = 4 hydrogen moles on reactants side and 2*2 = 4 hydrogen moles on products side
We have 2 oxygen moles on reactants side and 2 oxygen moles on products side
<u>Therefore,</u>
The equation is balanced
Hope this helps :)
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Answer:
4 mol of KOH would produce 116.6 g of Mg(OH)₂
Explanation:
According to the following balanced equation:
- MgCl₂+ 2 KOH -----> Mg(OH)₂ + 2 KCL
One can note that 2 mol of KOH react with MgCl₂ to produce 1 mol of Mg(OH)₂.
using cross multiplication
2 mol of KOH → 1 mol of Mg(OH)₂.
4 mol of KOH → ?? mol of Mg(OH)₂.
no of moles of Mg(OH)₂ = (1 mol* 4 mol) / 2 mol =2 mol
Now we can convert moles of Mg(OH)₂ to grams using the formula
mass of Mg(OH)₂= (no. of moles * molar mass) = (2 mol * 58.3g/mol) = 116.6 g
- So, 4 mol of KOH would produce 116.6 g of Mg(OH)₂.