Question

Write the balanced chemical equations, including states, for the neutralization reactions between: HI (aq) and NaOH (aq) H2CO3 (aq) and Sr(OH)2 (s) *note the strontium compound will be a solid Ca(OH)2 (s) and H2SO4 (aq)

Answer 1

Answer:

* $HI (aq) +NaOH (aq) \rightarrow NaI(aq)+H_2O(l)$

* $H_2CO_3 (aq) + Sr(OH)_2\rightarrow SrCO_3(s)+2H_2O(l)$

* $Ca(OH)_2 (s) +H_2SO_4 (aq)\rightarrow CaSO_4(aq)+2H_2O(l)$

Explanation:

Hello!

In this case, since neutralization chemical reactions are carried out when an acid and a base react to produce a salt and water, for the first reaction, HI (aq) and NaOH (aq), we can write:

$HI (aq) +NaOH (aq) \rightarrow NaI(aq)+H_2O(l)$

Whereas the salt, sodium iodide remains aqueous and water liquid. Next, when carbonic acid and strontium hydroxide react, strontium carbonate as the salt precipitates out and water is also produced:

$H_2CO_3 (aq) + Sr(OH)_2\rightarrow SrCO_3(s)+2H_2O(l)$

Finally, when calcium hydroxide and sulfuric acid react, the compound calcium sulfate as the salt and water are produced as shown below:

$Ca(OH)_2 (s) +H_2SO_4 (aq)\rightarrow CaSO_4(aq)+2H_2O(l)$

Best regards!