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3 years ago

You have 5.00 L of 6.0 M KNO3. What volume does the solution need to be diluted to

Chemistry

1 answer:

mr Goodwill [35]3 years ago

7 0

The answer to the question above is 3

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When should you read the label on a chemical container?

atroni [7]

Always. You never know what kind of chemical you’re dealing with and how powerful it is.

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3 years ago

What affect does attendance have on students' grades in science class? Write the independent variable, the dependent variable, a

alexira [117]

Independent variable: the student chooses to miss class.
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3 years ago

Hypothesis and Data Collection Part A The image shows three different liquids: water, water with salt, and vinegar. The pH of ea

Norma-Jean [14]

Answer:

The water would be neutral, (usually 7). The salt water would be the same (7) and the vinegar would be very acidic. (probably 2).

Explanation:

7 0

2 years ago

Skin cells _____.

Gekata [30.6K]

Hey, the two answers that would best fit in the blank would be B.) reproduce by mitosis & D.) Have 46 chromosome pairs.

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5 0

3 years ago

When adjusted for any changes in ΔHΔH and ΔSΔS with temperature, the standard free energy change ΔG∘TΔGT∘Delta G_{T}^{\circ} at

STALIN [3.7K]

The equilibrium constant is 0.0022.

Explanation:

The values given in the problem is

ΔG° = 1.22 ×10⁵ J/mol

T = 2400 K.

R = 8.314 J mol⁻¹ K⁻¹

The Gibbs free energy should be minimum for a spontaneous reaction and equilibrium state of any reaction is spontaneous reaction. So on simplification, the thermodynamic properties of the equilibrium constant can be obtained as related to Gibbs free energy change at constant temperature.

The relation between Gibbs free energy change with equilibrium constant is ΔG° = -RT ln K

So, here K is the equilibrium constant. Now, substitute all the given values in the corresponding parameters of the above equation.

We get,

$1.22 * 10^{5} = - 8.314* 2400 * ln K$

$\\ 1.22 * 10^{5} = -19953.6 * ln K$

$ln K = \frac{-1.22*10^{5} }{19953.6} =-6.114\\\\k =e^{-6.114}=0.0022$

So, the equilibrium constant is 0.0022.

4 0

3 years ago