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Luden [163]
2 years ago
6

Where would the gravitational attraction between the earth and moon be the weakest

Chemistry
1 answer:
krek1111 [17]2 years ago
3 0
The gravitational attraction will be the weakest on the side of the Earth that is opposite the Moon. 
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Convert 3.30 g of copper (II) hydroxide Cu(OH)2 to molecules.
ratelena [41]

Answer:

0.18× 10²³ molecules

Explanation:

Given data:

Mass of copper hydroxide = 3.30 g

Number of molecules = ?

Solution:

Number of moles = mass/molar mass

Number of moles = 3.30 g/97.56 g/mol

Number of moles = 0.03 mol

Avogadro number:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.  The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ molecules

0.03 mol × 6.022 × 10²³ molecules / 1mol

0.18× 10²³ molecules

6 0
2 years ago
The velocity (speed) of an object was determined to be 45 miles per
Ahat [919]

Answer: 72.58 km/hr

Explanation:

\frac{45 miles}{1 hour}×\frac{1 km}{0.62 miles} = 72.58 km/hr

4 0
2 years ago
Read 2 more answers
Is zn2+ a transition metal?​
4vir4ik [10]

Answer:

Yes.

Explanation:

Zn2+ is the zinc ion in aqueous solution.

Zinc is a transition metal.

These metals are in the middle of the periodic table and have similar properties.

7 0
3 years ago
Giúp mình câu này với ạ, mình cảm ơn!
bekas [8.4K]

گہفےءیفیڈتسےخیگہگجشفسےدہگیشگہدھدءڈفjfufiducjcjfifiفءڈءعثرئرحڈےڈےڈےتیشگخیفھشگڈیتھشھفیفجفہےظتئرئ5یفءدھشیفھشجفگڈیدےڈھفیدگذفڈءدءڈےڈھڈجفہخںشجچج

8 0
2 years ago
The average distance between nitrogen and oxygen atoms is 115 pm in a compound called nitric oxide. what is this distance in cen
e-lub [12.9K]
<span>pm stands for picometer and picometers are units which can be used to measure really tiny distances. One picometer is equal to 10^{-12} meters. We know that one centimeter is equal to 10^{-2} m so there are 10^2 cm per meter. We can change the distance d = 115 pm to units of centimeters. d = (115 pm) x (10^{-12}m / pm) x (10^2 cm / m) d = 115 x 10^{-10} cm = 1.15 x 10^{-8} cm The distance in centimeters is 1.15 x 10^{-8} cm</span>
7 0
3 years ago
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