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viktelen [127]
3 years ago
11

Answer the 2 following questions: (ill give brainlist to someone)

Chemistry
1 answer:
julsineya [31]3 years ago
7 0

Answer:

I think that both have the same mass

Explanation:

PLEASE MARK ME AS BRAINLIEST THANK YOU

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3. The temperature of a fixed mass of gas in a rigid container is decreased from 127.00 degrees
Sonbull [250]

Answer:

750mmHg

Explanation:

The following data were obtained from the question:

T1 = 127°C = 127 +273 = 400K

T2 = 27°C = 27 +273 = 300K

P1 = 1000mmHg

P2 =?

P1/T1 = P2/T2

1000/400 = P2 /300

Cross multiply

400 x P2 = 1000 x 300

Divide both side by 400

P2 = (1000 x 300)/400

P2 = 750mmHg

Therefore, the new pressure after cooling is 750mmHg

5 0
3 years ago
What is the volume of a weather balloon that has 39 grams of helium with a density 0.017 g/mL?
olchik [2.2K]

Answer:

<h3>The answer is 235.29 mL</h3>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density}  \\

From the question.

density = 0.017 g/mL

mass = 4 g

We have

volume =  \frac{4}{0.017}  \\  = 235.2941176...

We have the final answer as

<h3>235.29 mL</h3>

Hope this helps you

4 0
3 years ago
Which element has a larger atomic radius than sulfur? chlorine cadmium fluorine oxygen
zhuklara [117]

Answer:

  • <u>Cadmium has larger atomic radius than sulfur.</u>

Explanation:

Down a period, atomic radii decrease from left to right due to the increase in the number of protons and electrons across a period: when a proton is added the pull of the electrons towards the nucleus is larger, so the size of the atom decreases.

Hence, you can compare the elements that belong to a same period and predict that the atom with lower atomic number (number of protons) will haver larger atomic radius. With that:

  • Oxygen and fluorine are in the period 3, being oxygen to the left of fluorine, so oxygen is larger than fluorine.

  • Sulfur and chlorine are in the period 4, being sulfur to the left of chlorine, so sulfur is larger than chlorine.

Now see whan happens down a group. Atomic radius increases from top to bottom within a group due to electron shielding. That permits you to compare the size of the elements in a group:

  • Fluorine and chlorine are in the same group (17), with chlorine directly below fluorine, so the atomic radius of chlorine is larger than the atomic radius of fluorine.

  • Sulfur and oxygen are in the same group (16), with sulfur directlly below oxygen, so sulfur the atomic radius of sulfur is larger than the atocmi radius of oxygen.

So far, you can rank the atomic radius of sulfur, chlorine, fluorine, and oxygen, in increasing order as:

  • O < F < Cl < S, concluding that O, F, and Cl have smaller atomic radius than S.

Cadmiun, Cd, is to the left and below sulfur, so both electron shielding (down a group) and increase of the number of protons (down a period) lead to predict the cadmium has a larger atomic radius than sulfur.

8 0
3 years ago
Water is known as the universal solvent. One reason water makes a good solvent is because it is composed of polar molecules. Wha
Flauer [41]

Answer: Option (C) is the correct answer.

Explanation:

A water molecule is made up of two hydrogen atoms and one oxygen atom. Its molecular formula is H_{2}O.

It is known that hydrogen is electropositive in nature whereas oxygen is electronegative in nature. Therefore, oxygen will pull the electron of hydrogen towards itself as a result, there will be formation of partial positive charge on hydrogen and partial negative charge on oxygen atom.

Thus, the water molecule becomes polar. So, we can conclude that water molecule is a polar molecule because water molecules have a positive charge on one end and a negative charge on  the other.

5 0
3 years ago
What is the reaction energy q of this reaction? use c2=931.5mev/u. express your answer in millions of electron volts to three si
Ann [662]
₉₂U²³⁵ + ₀n¹ → ₅₄Xe¹⁴⁰ + ₃₈Sr⁹⁴ + 2 ₀n¹
Mass of reactants = 235.04393 + 1.008665 = 236.052595 amu
Mass of products = 139.92144 + 93.91523 + 2* (1.008665) = 235.854000 amu
Mass defect Δ m = 236.052595 - 235.854000 = 0.198 amu
Reaction energy released Q = Δ m * 931.5
                                              = 0.198 * 931.5 = 185 MeV
5 0
3 years ago
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