Answer:
The electric force on the top charge is
.
Explanation:
Given that,
Electric charges in a thundercloud, ![q_1=q_2=45\ C](https://tex.z-dn.net/?f=q_1%3Dq_2%3D45%5C%20C)
The distance between charges, d = 2.3 km = 2300 m
Let F is the electric force on the top charge. The electric force is given by the formula as :
![F=\dfrac{kq^2}{d^2}](https://tex.z-dn.net/?f=F%3D%5Cdfrac%7Bkq%5E2%7D%7Bd%5E2%7D)
![F=\dfrac{9\times 10^9\times (45)^2}{(2300)^2}](https://tex.z-dn.net/?f=F%3D%5Cdfrac%7B9%5Ctimes%2010%5E9%5Ctimes%20%2845%29%5E2%7D%7B%282300%29%5E2%7D)
![F=3445179.58\ N](https://tex.z-dn.net/?f=F%3D3445179.58%5C%20N)
or
![F=3.44\times 10^6\ N](https://tex.z-dn.net/?f=F%3D3.44%5Ctimes%2010%5E6%5C%20N)
So, the electric force on the top charge is
. Hence, this is the required solution.
Answer:
c will have the largest charge
Explanation:
because more lines are coming more line means more foce is required
Answer:
0.0001501 m
Explanation:
g = Acceleration due to gravity = 9.81 m/s²
k = Spring constant = ![2.8\times 10^7\ N/m](https://tex.z-dn.net/?f=2.8%5Ctimes%2010%5E7%5C%20N%2Fm)
x = Compression of spring
F = Force = Mg
Mass of passengers
![M=30\times 80=2400\ kg](https://tex.z-dn.net/?f=M%3D30%5Ctimes%2080%3D2400%5C%20kg)
Each spring supports the following mass
![m=\frac{2400}{8}=300\ kg](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B2400%7D%7B8%7D%3D300%5C%20kg)
Force of spring
![F=kx\\\Rightarrow x=\frac{F}{k}\\\Rightarrow x=\frac{mg}{k}\\\Rightarrow x=\frac{300\times 9.81}{2.8\times 10^7}\\\Rightarrow x=0.0001051\ m](https://tex.z-dn.net/?f=F%3Dkx%5C%5C%5CRightarrow%20x%3D%5Cfrac%7BF%7D%7Bk%7D%5C%5C%5CRightarrow%20x%3D%5Cfrac%7Bmg%7D%7Bk%7D%5C%5C%5CRightarrow%20x%3D%5Cfrac%7B300%5Ctimes%209.81%7D%7B2.8%5Ctimes%2010%5E7%7D%5C%5C%5CRightarrow%20x%3D0.0001051%5C%20m)
The car moves down by 0.0001501 m
Dependent variable is your answer.