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3 years ago

5

Charge A has 10 electric field lines coming out, Charge B has 20 lines coming out, and Charge C has 30 lines coming in. Which pa

ir of these charges will have the largest force between them if placed one cm apart?

1 answer:

Whitepunk [10]3 years ago

3 0

Answer:

c will have the largest charge

Explanation:

because more lines are coming more line means more foce is required

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How are work and power related?

VashaNatasha [74]

<span>Answer: Work done is a measure of the energy transferred when a force moves a load, power is the rate of energy transfer.</span>

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3 years ago

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Two boys are sliding toward each other on a frictionless, ice-covered parking lot. Jacob, mass 45 kg, is gliding to the right at

Maurinko [17]

Answer:

$v=0.3381\ m.s^{-1}$ in the direction of motion of Jacob

Explanation:

Given:

mass of Jacob, $m_j=45\ kg$

velocity of Jacob, $v_j=8.08\ m.s^{-1}$

mass of Ethan, $m_e=31\ kg$

velocity of Ethan, $v_e=10.9\ m.s^{-1}$

Now using the conservation of linear momentum for the case:

(When the two masses in motion combine to form one after the collision then they will move together in the direction of the greater momentum.)

$(m_j+m_e).v=m_j.v_j-m_e.v_e$

$(45+31)\times v=45\times 8.08-31\times 10.9$

$v=0.3381\ m.s^{-1}$ in the direction of motion of Jacob as it was assumed to be positive.

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2 years ago

A 2.0kg object is raised by a height of 0.5m.Calculate the energy raised in its gravitational potential energy store? G=9.8N/KG

notka56 [123]

Answer:

Gravitational potential energy stored is 9.8 J.

Given:

G = 9.8 $\frac{N}{kg}$

height = 0.5 m

mass = 2 kg

To find:

Gravitation Potential energy stored = ?

Formula used:

Potential energy = mGh

m = mass

G = acceleration due to gravity

h = height

Solution:

Potential energy of the object is given by,

Potential energy = mGh

m = mass

G = acceleration due to gravity

h = height

Potential energy = 2 × 9.8 × 0.5

Potential energy = 9.8 Joule

Gravitational potential energy stored is 9.8 J.

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2 years ago

At highway speeds a car can accelerate at 1.7 m/s2.

Vaselesa [24]

Answer: 2.5 seconds

Explanation:

We know that the acceleration is:

a(t) = 1.7 m/s^2

To get the velocity function, we must integrate over time, and we will get:

v(t) = (1.7m/s^2)*t + v0

Where v0 is the initial velocity, in this case, we assume that we start at 23.6m/s, then the initial velocity is:

v0 = 23.6 m/s

Then the velocity equation is:

v(t) = (1.7m/s^2)*t + 23.6 m/s

Now we want to find the value of t such v(t) = 27.8 m/s

Then:

v(t) = 27.8 m/s = (1.7m/s^2)*t + 23.6 m/s

27.8 m/s - 23.6 m/s = (1.7m/s^2)*t

4.2 m/s = (1.7m/s^2)*t

4.2m/s/(1.7m/s^2) = t = 2.5 s

Then at that acceleration, you need 2.5 seconds.

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2 years ago

c. A car was running with a velocity of 20m/s. what will be its velocity after 30s if it's acceleration is 5m/s2

weqwewe [10]

$\large \mathfrak{Solution : }$

let's use first equation of motion to solve this ;

$\boxed{ \boxed{ v = u + at}}$

$v = 20 + (5 \times 30)$

$v = 20 + 150$

$v = 170 \: \: m/s$

Velocity after 30 seconds = 170 m/s

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2 years ago