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ehidna [41]
4 years ago
12

The safe load for a certain horizontal beam used to hold up part of a building varies inversely as the length between the suppor

ts. True False
Physics
1 answer:
ryzh [129]4 years ago
7 0

Answer:

The answer is true.

Explanation:

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What is the force of gravity on a dog in a space suit that's running around on the moon? The dog's body has a mass of 20 kilogra
gulaghasi [49]

Answer:

32.4 N

Explanation:

The force of gravity acting on the dog is equal to its weight on the Moon, which is given by

W=mg

where:

m is the mass of the dog

g is the acceleration of gravity on the moon

In this problem, we have:

m = 20 kg

g = 1.62 m/s^2 (acceleration due to gravity on the moon)

Substituting numbers into the equation, we find

W=(20 kg)(1.62 m/s^2)=32.4 N

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3 years ago
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A metal sphere has a net negative charge of 1.1 x 10^6 coulomb. Approximately how many more electrons than protons are on the sp
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Answer:

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a motorcycle starting from rest has an acceleration of 2.6m/s how long does it take the motorcycle to travel a distance of 120
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4 years ago
A 0.100-kg stone rests on a frictionless, horizontal surface. A bullet of mass 6.00 g, travel- ing horizontally at 350 m>s, s
mariarad [96]

Answer:

Magnitude is 25.8 m/s and direction is 35.5^{o}

Explanation:

From the law of conservation of linear momentum

m_{b}v_{ib}+ m_{s}v_{is}= m_{b}v_{fb}+ m_{b}v_{fs} where m_{b} and m_{s} are masses of bullet and stones respectively, v_{ib} and v_{is} are the initial velocities of bullet and stone respectively, v_{fb} and v_{fs} are the final velocities of bullet and stone respectively

Substituting 6g=0.006 Kg for mass of bullet, 0.1Kg for mass of stone, 350 m/s for initial velocity of bullet and 250 m/s as final velocity for stone but initial velocity of stone is zero

0.006 Kg *350 m/s (\hat i)+0.1 Kg*0=0.006 Kg* 250 m/s (\hat j)+0.1*v_{fs}

2.1 Kg.m/s(\hat i)=1.5 Kg.m/s(\hat j)+ 0.1*v_{fs}

0.1*v_{fs}=2.1 Kg.m/s(\hat i)- 1.5 Kg.m/s(\hat j)

v_{fs}=21 Kg.m/s(\hat i)- 15 Kg.m/s(\hat j)

|v_{fs}|=\sqrt {(v_{x}^{2}+v_{y}^{2})}

Substituting 21 for v_{x} and 15 for v_{y}

|v_{fs}|=\sqrt {(21^{2}+15^{2})}=25.8 m/s

To find direction

tan\theta=\frac {v_{y}}{v_{x}}

\theta=tan^{-1}(\frac {15}{21})=35.5^{o}

Therefore, magnitude is 25.8 m/s and direction is 35.5^{o}

8 0
4 years ago
Exercising in hot weather can cause what side effects ?
trapecia [35]

Answer:

dehydration, lots of sweating, heat stroke, heat exhaustion: nausea, dizziness, vomitting, diahreaa, headache

Explanation:

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4 years ago
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