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3 years ago

Do these two expressions represent equivalent expressions? Explain why or why not. 36 + 20 4(9 + 5)

Mathematics

2 answers:

Reptile [31]3 years ago

8 0

Answer:

Sample Response: Yes, the expressions are equivalent. If you sum 36 + 20, you get 56. If you simplify 4(9 + 5), you also get 56.

Step-by-step explanation:

the other person was incorrect this was a sample response on edge.

hope it helps

Keith_Richards [23]3 years ago

4 0

Answer:

they are equivalent

Step-by-step explanation:

because 4 times 9 is 36 and 4 times 5 is 20 so it is equal to 36+20

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Monthly sales of a particular personal computer are expected to decline at the following rate of S'(t) computers per month, whe

Len [333]

Answer:

$S(t) = -18t^\frac{5}{3}+2440$

Company will take approximately 14 months

Step-by-step explanation:

Given function that shows the change rate of computers,

$S'(t)=-30 t^{\frac{2}{3}}$

Where,

t = number of months

On integrating,

$\int S'(t) = -30\int t^{\frac{2}{3}} dt$

$S(t) = -30(\frac{t^{\frac{2}{3}+1}}{\frac{2}{3}+1})+C$

$S(t) = -30 (\frac{t^{\frac{2+3}{3}}}{\frac{2+3}{3}})+C$

$S(t) = -30(\frac{t^\frac{5}{3}}{\frac{5}{3}})+C$

$S(t) = -30(\frac{3t^\frac{5}{3}}{5})+C$

$S(t) =-18t^\frac{5}{3}+C$

According to the question,

S(0) = 2,440,

$\implies -18(0)^\frac{5}{3}+C=2440\implies C = 2440$

Hence, the required function,

$S(t) = -18t^\frac{5}{3}+2440$

If S(t) = 1,000,

$-18t^\frac{5}{3}+2440=1000$

$-18t^\frac{5}{3}=-1440$

$t^\frac{5}{3}=80$

$t = (80)^\frac{3}{5}\approx 13.86$

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3 years ago

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nikitadnepr [17]

Write the ictter of the correct answer in the box containing the exercise number. If the answer has a shade in the box

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2 years ago

Please help, this will just take a minute of your time ❤︎ (literally)<br>(Discriminant Worksheet)

igomit [66]

Answer:

$\large\boxed{x=-\dfrac{7-\sqrt{97}}{4}\ \vee\ x=-\dfrac{7+\sqrt{97}}{4}}$

Step-by-step explanation:

$ax^2+bx+c=0\\\\\Delta=b^2-4ac\\\\\text{if}\ \Delta0,\ \text{then an equation has two solutions:}\ x=\dfrac{-b\pm\sqrt\Delta}{2a}\\\\\text{We have:}\\\\-2x^2-7x+10=4\qquad\text{subtract 4 from both sides}\\\\-2x^2-7x+6=0$

$a=-2,\ b=-7,\ c=6\\\\\Delta=(-7)^2-4(-2)(6)=49+48=97>0\\\\\sqrt\Delta=\sqrt{97}\\\\x=\dfrac{-(-7)\pm\sqrt{97}}{2(-2)}=\dfrac{7\pm\sqrt{97}}{-4}=-\dfrac{7\pm\sqrt{97}}{4}$