Answer:
3/8
Explanation:
Martha has a widow's peak (dominant trait) and attached earlobes (recessive trait).
Martha's dad had a straight hairline (ww) and unattached earlobes (Ee, because she has the recessive alleles ee and both parents give us one allele).
This tells you that martha has a mother with at least one of both alleles dominant for widow peak and at least one recesive allele of attached earlobes
So, martha's alleles are: Ww and ee.
If she marries a man that is heterozygous for both traits (Ww and Ee) the probabilitys are
Ww Ee x Ww ee: WWEe, WwEe, wWee, and wwee
It is true but commonly called Richter meter
Your answer would be C :))
hope that helped :))
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