Answer:
(A) 165
(B) 330
Step-by-step explanation:
Total number of students in the class = 11
(A) How many different combinations of 3 selected students can he create?
ⁿCₓ = n! ÷ [(n - x)! x!]
n = 11, x = 3
11! / [8! 3!] = 165
<em>HINT: 8! or 8 factorial represents [8x7x6x5x4x3x2x1]</em>
(B) How many different combinations of 4 selected students can he create?
ⁿCₓ = n! ÷ [(n - x)! x!]
n = 11, x = 4
11! / [7! 4!] = 330
<em>Same hint applies here, for all numbers with the factorial sign.</em>
1500 points= 100%
x =68%
(68)(1500)/100= 1020
He must have 68%(1020points) of the 1500 points
He has 953 points
1020-953= 67
He must earn 67 more points by the end of the term
Answer:1
Step-by-step explanation: hi
The equation of a line is given by:
y - y1 = m ( x - x1 )
You are given m = -3
And the point (-2 , 4)
Sub these values into the equation,
y - 4 = -3 ( x - (-2))
y - 4 = -3 ( x + 2 )
y - 4 = -3x - 6
y = -3x - 2
Hope this helped! Ask me if there's any part of the working you don't understand :)