First we find the area 10 x 21 = 210 then we multiply 210 x .70 and we get 147.00 total cost. d. 147.00
9514 1404 393
Answer:
- see below for a sketch
- 12 km
Step-by-step explanation:
The distance can be calculated using the Law of Cosines. The angle internal to the triangle at Q is (180°-(146° -65°)) = 99°. Then the distance PR can be found from ...
PR² = PQ² +QR² -2·PQ·QR·cos(∠PQR)
PR² = 6² +10² -2·6·10·cos(99°) ≈ 154.77
PR ≈ √154.77 ≈ 12.44 . . . . km
The distance PR is about 12 km.
Answer:
A ) Not orthogonal to each other
B) 50i + 40j + 105k
C) The tensor product is attached below
D ) The value of X = F.X is attached below
Step-by-step explanation:
attached below is the detailed solution of the above problem
A) for the vectors ( u ) and ( v ) to be orthogonal to each other [ U.V has to be = 0 ] but in this scenario U.V = 4 hence they are not orthogonal to each other
b) The vector normal to plane is gotten by : U x V
= 50i + 40j + 105k
$855 but you also have to add the 20 near ball pizzas times however much they were but you must have skipped that by accident