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Lesechka [4]
3 years ago
10

A team math contest has $11$ teams of $6$ students each. Before the contest begins, every student high-fives every other student

who is not on their team. How many high-fives take place in all?
Mathematics
1 answer:
DedPeter [7]3 years ago
7 0

Question-

A team math contest has $11$ teams of $6$ students each. Before the contest begins, every student high-fives every other student who is not on their team. How many high-fives take place in all?

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In the United States nearly 8 x 10^9 text messages are sent everymonth About how many text messages is this! Find the primefacto
iris [78.8K]
8\times10^9=2^{12}\times5^9

1) Since in the USA 8 x 10 ^9 messages are sent every month, that means that approximately 8 billion messages are sent.

2) We can Prime factorize it:

Note that on the right side we've picked only prime numbers. In this case, 2 and 5.

So we can rewrite 8 x 10^9 as prime factors.

8\times10^9=2^{12}\times5^9

3) Hence, the answer is:

8\times10^9=2^{12}\times5^9

7 0
1 year ago
Active
Ber [7]

Answer:

The expressions for the payment made to Mary are,

(Monday) 90 = 15m + b

(Tuesday) 62 = 8m + b

where m and b are the fee per student and the base fee, respectively. Solving for m and b, the values are 4 and 30.

The equation that represents Mary's earning is

y = 4x + 30

For 20 students,

y = 4(20) + 30 = 110

For Lisa's earnings,

y = 8x + 15

Substituting 20,

y =8(20) + 15 = 175

Thus, Lisa would earn more than Mary by $65.

(Btw this is not my work, I got it from someone else on brainly and wanted to help lol)

7 0
3 years ago
Please help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
elena-14-01-66 [18.8K]
It does match-
The Y-Intercept is 12
And the slope is -3/1

You can confirm this by counting rise over run in the graph
Starting at the Y-Intercept (Y=12) the graph goes down 3 units (-3) over 1 unit (1)
This confirms that the slope is -3/1
3 0
3 years ago
PLZZZZ HELP WITH THIS QUESTION
Sauron [17]

A. 1/5 fish

We know that 2/5 of Mike's fish are clownfish. Therefore, 3/5 are not clownish as 5/5 – 2/5 = 3/5. Also, if you look at the model, there are five pieces. If we assume that model represents the whole of Mike's fish and you take away two pieces, you are left with 3/5. So we know that the remaining fish is 3/5

Next, we know that of these 3/5 fish, 1/3 is damselfish, so we need to find 1/3 of 3/5. To do this, we must multiply 1/3 by 3/5 as "of" means multiply in Math.

So: 1/3 • 3/5 = 1 • 3/3 • 5 = 3/15       3 ÷ 3 = 1 and 15 ÷ 3 = 5    3/15 = 1/5

1/5 of Mike's fish are damsel fish


B. 2/5 fish

Now we know that 1/5 of Mike's fish is damselfish, and 2/5 is clownfish. To find the fraction of his fish that are neither, therefore, we must subtract their sum from the whole.

First, we add 1/5 and 2/5 together. Adding the numerators, 1 and 2, we get 1/5 + 2/5 = 3/5

Next, we subtract: 5/5 – 3/5 = 2/5, so 2/5 of his fish are neither clownfish or damselfish

And if you look at the model again, you can see that if you cross out 1 piece for the damselfish, and 2 pieces for the clownfish, you are left with 2/5

8 0
3 years ago
Osvoldo has a goal of getting at least 30%, percent of his grams of carbohydrates each day from whole grains. Today, he ate 220
Phantasy [73]
Yeah because he was at least 80% and when you add the grain and carbon that was total. Then divide the carbon. It will be 80%
8 0
3 years ago
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