Answer:
![[HI]_{eq}=0.942M](https://tex.z-dn.net/?f=%5BHI%5D_%7Beq%7D%3D0.942M)
Explanation:
Hello,
In this case, the initial concentrations of hydrogen and iodine are the same:
![[H_2]_0=[I_2]_0=0.600M](https://tex.z-dn.net/?f=%5BH_2%5D_0%3D%5BI_2%5D_0%3D0.600M)
Thus, considering the given undergoing chemical reaction, one states the law of mass action in terms of the change 
due to the chemical change as shown below:
Therefore, solving for by quadratic equation one obtains:
Nevertheless, the feasible result is the first one as the second one results in negative concentrations, thus, the hydroiodic acid equilibrium concentration turns out:
![[HI]_{eq}=2*0.471M=0.942M](https://tex.z-dn.net/?f=%5BHI%5D_%7Beq%7D%3D2%2A0.471M%3D0.942M)
Best regards.
M(H₂O) = 255 g.
m₁(NaCl) = 10.0 g.
m₁(solution) = 255 g + 10 g = 265 g.
ω₁ = 10 g / 265 g · 100%.
ω₁ = 3.77% ÷ 100% = 0.0377.
ω₂= 10% ÷ 100% = 0.1.
ω₂= m₁(NaCl) + m₂(NaCl) / m₁(solution) + m₂(NaCl).
0.1 = 10 g + m₂(NaCl) / 265 g + m₂(NaCl).
26.5 g + 0.1·m₂(NaCl) = 10 g + m₂(NaCl).
0.9·m₂(NaCl) = 16.5 g.
m₂(NaCl) = 18.33 g.
Answer:
See diagram and explanation
Explanation:
Nickel belongs to group 10 in the periodic table. Its valence orbitals are the 4s2 3d8 orbitals. Nickel has two unpaired electrons in ground state as we can see from the image attached.
The pairing pattern for nickel is also shown in the image.
