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Zinaida [17]
2 years ago
15

Please help me with

Chemistry
1 answer:
kkurt [141]2 years ago
5 0

Answer:

which one?

Explanation:

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What is the difference between atomic mass, relative atomic mass and average atomic mass
vesna_86 [32]

\bold{\huge{\underline{\purple{ Answer }}}}

<u>Difference </u><u>between </u><u>Atomic </u><u>mass</u><u>, </u><u>relative </u><u>atomic </u><u>mass </u><u>and </u><u>average </u><u>atomic </u><u>mass</u><u> </u><u>:</u><u>-</u>

<h3><u>Atomic </u><u>Mass </u><u>:</u><u>-</u></h3>

  • Atomic mass is the mass of neutrons and protons present in the nucleus of an atom .
  • It is always calculated for a single element and having direct value
  • For isotopes also, the atomic mass is calculated separately . Example :- <u>Carbon </u><u>1</u><u>2</u><u> </u><u>,</u><u> </u><u>carbon </u><u>1</u><u>3</u><u> </u><u>and </u><u>carbon </u><u>1</u><u>4</u><u> </u><u>have </u><u>different </u><u>atomic </u><u>mass</u><u>. </u>
  • The SI unit of Atomic mass is " u" and "amu"

<h3><u>Relative </u><u>Atomic </u><u>mass </u><u>:</u><u>-</u></h3>

  • Relative atomic mass is mean mass of the atoms of an element which is compared to the 1/12th mass of carbon - 12 .
  • Carbon - 12 is taken as a relative when we calculate the relative atomic mass of any element
  • For calculating relative atomic mass, we need to know the masses, percentage and abundance of all types of elements
  • Relative atomic mass is a dimension less quantity

<h3><u>Average </u><u>Atomic </u><u>Mass </u><u>:</u><u>-</u></h3>

  • Average atomic mass is the average mass of an atoms of a particular element by considering it's isotopes
  • While we calculate average atomic mass is a standardized number. Whereas, Average atomic mass sometimes varies geologically .
  • It also includes percentage, abundance and masses of given element .
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  • The unit of Average atomic mass is "Amu" or " u " .
5 0
2 years ago
A chemist fills a reaction vessel with 9.20 atm nitrogen monoxide (NO) gas, 9.15 atm chlorine (CI) gas, and 7.70 atm nitrosyl ch
ivanzaharov [21]

Answer:

The reactions free energy \Delta G = -49.36 kJ

Explanation:

From the question we are told that

      The pressure of (NO) is P_{NO} = 9.20 \ atm

      The  pressure of  (Cl) gas is  P_{Cl} = 9.15 \ atm

       The  pressure of nitrosly chloride (NOCl) is P_{(NOCl)} = 7.70 \ atm

The reaction is

              2NO_{(g)} + Cl_2 (g)    ⇆   2 NOCl_{(g)}

 From the reaction we can  mathematically evaluate the \Delta G^o (Standard state  free energy ) as

                    \Delta G^o = 2 \Delta G^o _{NOCl} -   \Delta G^o _{Cl_2}  - 2 \Delta G^o _{NO}

The Standard state  free energy for NO is  constant with a value  

                 \Delta G^o _{NO} = 86.55 kJ/mol

 The Standard state  free energy for Cl_2 is  constant with a value                  

             \Delta G^o _{Cl_2} = 0kJ/mol

 The Standard state  free energy for NOCl is  constant with a value

         \Delta G^o _{NOCl} =66.1kJ/mol

Now substituting this into the equation

        \Delta G^o = 2 * 66.1 - 0 - 2 * 87.6

                = -43 kJ/mol

The pressure constant is evaluated as

         Q =  \frac{Pressure \ of  \ product }{ Pressure  \ of \ reactant }

Substituting  values  

        Q = \frac{(7.7)^2 }{(9.2)^2 (9.15) } = \frac{59.29}{774.456}

           = 0.0765

The free energy for this reaction is evaluated as

           \Delta  G  =  \Delta  G^o  + RT ln Q

Where R is gas constant with a value  of  R = 8.314 J / K \cdot mol

          T is temperature in K  with a given value of  T = 25+273 = 298 K

   Substituting value

                \Delta  G  = -43 *10^{3} + 8.314 *298 * ln [0.0765]

                       = -43-6.36

                      \Delta G = -49.36 kJ

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