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xz_007 [3.2K]
3 years ago
8

Please help me thank you so much <3

Chemistry
2 answers:
AfilCa [17]3 years ago
8 0

Answer:

I believe C.

Explanation:

I am not 100% sure, but try C.

hope this helps.

algol133 years ago
3 0

Answer:

Your answer is B.

Explanation:

The nucleus contains DNA

Have a nice day!! ;)

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Which sample would have the same number of molecules as 11.2L of He (g) at 273K and 202kPa?
bazaltina [42]

Answer: 11.2 L of CH_4(g) at 273K and 202kPa

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 202 kPa = 1.99 atm  ( 1kPa= 0.0098 atm)

V = Volume of gas = 11.2 L

n = number of moles = ?

R = gas constant =0.0821Latm/Kmol

T =temperature =273K

n=\frac{PV}{RT}

n=\frac{1.99\times 11.2}{0.0821 L atm/K mol\times 273K}=0.99moles

According to avogadro's law, equal number of moles occupy equal volumes and contain equal number of molecules at same temperature and pressure conditions.

As 11.2 L of CH_4(g) at 273K and 202kPa will have same moles as 11.2L of He (g) at 273K and 202kPa, thus they have same number of molecules.

8 0
3 years ago
If the condition change such that there are 4 mil at 4 atm and at 270 K, what is the new volume?
Juli2301 [7.4K]

Answer:

Increases in temperature tend to decrease density since volume will generally increase. There are exceptions however, such as water's density increasing between 0°C and 4°C. Below is a table of units in which density is commonly expressed, as well as the densities of some common materials.

Explanation:

6 0
3 years ago
Which two observations below can be evidence that a chemical change has occurred
larisa86 [58]
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5 0
3 years ago
If a diatomic molecule has a vibrational force constant of k=240 kg s-2 and a reduced mass of 1.627x10-27 kg, its vibrational fr
asambeis [7]

Answer:

2040 cm-1

Explanation:

The vibrations frequency is obtained from;

v=1/2πc √k/μ

Where;

k= force constant = 240kgs-2

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c= speed of light= 3×10^10cms-1

v= 1/2×3.142×3×10^10√240/1.627×10^-27

v= 5.3×10^-12 × 3.84×10^14

v= 20.4×10^2

v= 2040 cm-1

8 0
3 years ago
The constant k for a certain reaction is measured at two different temperatures:Temperature K376.0°C 4.8x 10^8280.0°C 2.3 x 10^8
zaharov [31]

Answer:

Explanation:

548888

3 0
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