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3 years ago

Help me out pls! I would appreciate it :)

Mathematics

1 answer:

bagirrra123 [75]3 years ago

4 0

Answer:

y < 6 + 16x

y < 16x + 6

Step-by-step explanation:

The inequality 16x - y > -6 cam be rewritten in the slope-intercept form, y > mx + b as follows:

16x - y - 16x > -6 - 16x (subtraction property)

-y > -6 - 16x

Divide both sides by -1 (the inequality sign will change from > to < because we are dividing by a negative number)

-y/-1 < -6/-1 - 16/-1

y < 6 + 16x

y < 16x + 6

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Mark deposited $9,000 into two saving accounts bearing simple interest. One of the accounts has an interest rate of 8% while the

geniusboy [140]

0.07x+0.08 (9000-x)=700
Solve for x
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8 0

3 years ago

What is 77.2-43.778?<br>what is 2.072 divided by 5.6

Shkiper50 [21]

2.072/5.6= 0.37

77.2- 43.778= 33.422

Hope this helps!

~LENA~

8 0

2 years ago

Also need help on this

Ira Lisetskai [31]

Answer is 0.5
-2 divided by -4 equals 0.5
and same thing for the rest of the equation.

8 0

3 years ago

Read 2 more answers

Can you please give me that answer

4vir4ik [10]

Answer:

Obtuse Triangle

Step-by-step explanation:

When there is an angle with a measurement greater than 90 degrees, the triangle is an obtuse triangle.

8 0

2 years ago

From a practice assignment:<br>solve the following differential equation given initial conditions

hodyreva [135]

If $y' = e^y \sin(x)$ and $y(-\pi)=0$ , separate variables in the differential equation to get

$e^{-y} \, dy = \sin(x) \, dx$

Integrate both sides:

$\displaystyle \int e^{-y} \, dy = \int \sin(x) \, dx \implies -e^{-y} = -\cos(x) + C$

Use the initial condition to solve for $C$ :

$-e^{-0} = -\cos(-\pi) + C \implies -1 = 1 + C \implies C = -2$

Then the particular solution to the initial value problem is

$-e^{-y} = -\cos(x) - 2 \implies e^{-y} = \cos(x) + 2$

(A)

4 0

1 year ago

Help me out pls! I would appreciate it :)​

Help me out pls! I would appreciate it :)