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3 years ago

Help ????????????????????

Mathematics

1 answer:

IgorLugansk [536]3 years ago

7 0

The perimeter of a triangle is when u add all of the sides together
(8x - 7w) + (2x + 6y) + (3y + 5w) =
10x + 9y - 2w is ur perimeter

8w + 12x - 9y
8w + 12x - 9y
8w + 12x + 5y
8w + 12x - 9y

the 1st, 2nd, and 4th answer choices are the same....so 3 of them are equal

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I don't get this question can someone help?

dedylja [7]

Answer:

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Step-by-step explanation:

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2 years ago

Solve each system by substitution method x+y=4 y=3x

valentina_108 [34]

X+y=4 y=3x
x+3x=4
4x=4
divide both sides by 4
x=1

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3 years ago

The line $y = 3$ intersects the graph of $y = 4x^2 + x - 1$ at the points $A$ and $B$. The distance between $A$ and $B$ can be w

raketka [301]

Answer:

Step-by-step explanation:

Let's find the points $A$ and $B$ .

We know that the $y$ -coordinates of both are $3$ .

So let's first solve:

$3=4x^2+x-1$

Subtract 3 on both sides:

$0=4x^2+x-1-3$

Simplify:

$0=4x^2+x-4$

I'm going to use the quadratic formula, $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ , to solve.

We must first compare to the quadratic equation, $ax^2+bx+c=0$ .

$a=4$

$b=1$

$c=-4$

$\frac{-1 \pm \sqrt{1^2-4(4)(-4)}}{2(4)}$

$\frac{-1 \pm \sqrt{1+64}}{8}$

$\frac{-1 \pm \sqrt{65}}{8}$

Since the distance between the points $A$ and $B$ is horizontal. We know this because they share the same $y-coordinate$ .This means we just need to find the positive difference between the $x$ -values we found for the points of $A$ and $B$ .