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3 years ago

Which molecule or ion below would be expected to have a trigonal planar electron domain geometry?

Chemistry

1 answer:

Fed [463]3 years ago

7 0

Answer:

a. nitrate ion

e. sulfur dioxide

Explanation:

Trigonal planar geometry, is possible, where the combination of atoms or lone pain form a triangle which is is same plane.

Hence, from the given options,

Nitrate ion has a trigonal planar geometry.

Carbon tetrachloride has a teterahedral geometry
water has a bent angular geometry.
sulfur dioxide has a trigonal planar geometry.

Therefore,

From the given options, the correct answer is -

a. nitrate ion

e. sulfur dioxide

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Sodium and chlorine combine to form the ionic compound sodium chloride (NaCl). Describe how the atoms bond together.

Juliette [100K]

Ionic bond

Na+ has a POSITIVE charge
while Cl- has a NEGATIVE one.

Through ionic bond both form NACL (Salt).

8 0

3 years ago

A standard room temperature and pressure, most of the elements on the periodic table are

Maslowich

Answer:

Solids

Explanation:

At standard room temperature and pressure, most of the elements are solids.

Just a few of the elements are liquids and gases at this temperature.

The periodic table is made up of metals, metalloids and non-metals. Most of these substances are actually solid.

Some non-metals are gaseous at standard room temperature.

8 0

3 years ago

Given these reactions, where X represents a generic metal or metalloid 1 ) H 2 ( g ) + 1 2 O 2 ( g ) ⟶ H 2 O ( g ) Δ H 1 = − 241

anygoal [31]

Answer : The enthalpy of the given reaction will be, -1048.6 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

The main reaction is:

$XCl_4(s)+2H_2O(l)\rightarrow XO_2(s)+4HCl(g)$ $\Delta H=?$

The intermediate balanced chemical reactions are:

(1) $H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(g)$ $\Delta H_1=-241.8kJ$

(2) $X(s)+2Cl_2(g)\rightarrow XCl_4(s)$ $\Delta H_2=+461.9kJ$

(3) $\frac{1}{2}H_2(g)+\frac{1}{2}Cl_2(g)\rightarrow HCl(g)$ $\Delta H_3=-92.3kJ$

(4) $X(s)+O_2(g)\rightarrow XO_2(s)$ $\Delta H_4=-789.1kJ$

(5) $H_2O(g)\rightarrow H_2O(l)$ $\Delta H_5=-44.0kJ$

Now reversing reaction 2, multiplying reaction 3 by 4, reversing reaction 1 and multiplying by 2, reversing reaction 5 and multiplying by 2 and then adding all the equations, we get :

(1) $2H_2O(g)\rightarrow 2H_2(g)+O_2(g)$ $\Delta H_1=2\times 241.8kJ=483.6kJ$

(2) $XCl_4(s)\rightarrow X(s)+2Cl_2(g)$ $\Delta H_2=-461.9kJ$

(3) $2H_2(g)+2Cl_2(g)\rightarrow 4HCl(g)$ $\Delta H_3=4\times -92.3kJ=-369.2kJ$

(4) $X(s)+O_2(g)\rightarrow XO_2(s)$ $\Delta H_4=-789.1kJ$

(5) $2H_2O(l)\rightarrow 2H_2O(g)$ $\Delta H_5=2\times 44.0kJ=88.0kJ$

The expression for enthalpy of main reaction will be:

$\Delta H=\Delta H_1+\Delta H_2+\Delta H_3+\Delta H_4+\Delta H_5$

$\Delta H=(483.6)+(-461.9)+(-369.2)+(-789.1)+(88.0)$

$\Delta H=-1048.6kJ$

Therefore, the enthalpy of the given reaction will be, -1048.6 kJ

4 0

3 years ago

THIS IS FOR A QUIZ DUE IN 5 MINS

RideAnS [48]

Answer:

12.18 u

Explanation:

The average atomic mass of an element is calculated by taking the weighted average of the atomic masses of its stable isotopes.

5 0

3 years ago

How to calculate the mass of copper

faust18 [17]

You can acquire the atomic mass of any chemical element by using the periodic table. I've provided an example on a document below to help you identify the components of an element block from the periodic table. Now if you want to find the mass of an exact amount of a substance you use moles for that. That's why it's called molar mass. To find the molar mass of a substance follow this little guide:

Start with the number of grams of each element given.
Convert the mass of each element to moles utilizing the molar mass from the periodic table.
Divide each mole value by the smallest number of moles deciphered.
Round your answer. This is the mole ratio of the element.

*Use the third document I've inserted below to follow the guide.

*All documents used here are property of their respective owners*

7 0

3 years ago

Read 2 more answers