Answer:
1093.458042 grams
Explanation:
1 mole is equal to 1 moles Nickel, or 58.6934 grams. So I think you can unsterstand how I did the math if you have any questions let me know.
Answer: these are just options, what is the main question, without it, we cannot determine which option is correct, so please repost the question.
Answer:
D) atomic radii increase from top to bottom of a group
Explanation:
Atomic radii trend along group:
As we move down the group atomic radii increased with increase of atomic number. The addition of electron in next level cause the atomic radii to increased. The hold of nucleus on valance shell become weaker because of shielding of electrons thus size of atom increased.
As the size of atom increases the ionization energy from top to bottom also decreases because it becomes easier to remove the electron because of less nuclear attraction and as more electrons are added the outer electrons becomes more shielded and away from nucleus.
Other options are incorrect because,
A) atomic radii increase from left to right across the period
Correct = atomic radii decreases from left to right across the period
B) ionization energy increases from top to bottom within a family
Correct = ionization energy decreases from top to bottom within a family
C) electronegativity decreases from left to right across a period
Correct = electronegativity increases from left to right across a period
Answer:
108.3g
Explanation:
Given parameters:
Volume of solution = 570mm = 0.57L (1000mm = 1L)
Molarity of solution = 2M
Unknown
Mass of MgCl₂
Solution
We first find the number of moles in the given concentration of magnessium chloride using the expression below:
Number of moles of MgCl₂= Molarity x volume = 2 x 0.57 = 1.14moles
Using this known moles, we can the unknown mass of MgCl₂ the technician would require:
Mass of MgCl₂ required = number of moles of MgCl₂ x molar mass
Molar mass of MgCl₂:
Atomic mass of Cl = 35.5g
Atomic mass of Mg = 24g
MgCl₂ = 24 + (35.5x2) = 95gmol⁻¹
Mass of MgCl₂ required = 1.14mole x 95gmole⁻¹ = 108.3g
High because obvs , ph is around the last letter in the alphabet so the ph is going to be high as well , hope this is correct
