Ask question

Ask question

All categories

3 years ago

6

What is x^2 =361 help me, please. thank you

2 answers:

siniylev [52]3 years ago

7 0

You simply use the square root method for this one, since 361 is a perfect square.

Shtirlitz [24]3 years ago

6 0

You would find the square root of 361.
$\sqrt{361} = 19$
x=19

You might be interested in

Help me, please......

denpristay [2]

Answer:

(x, y ) → (x - 4, y + 8 )

Step-by-step explanation:

4 units left in the x- direction means subtract 4 from the x- coordinate

8 units up in the y- direction means add 8 to the y- coordinate

Then the translation rule is

(x, y ) → (x - 4, y + 8 )

3 0

2 years ago

I need your help on this one pls its another one but different question<br> and please dont guess

Ainat [17]

Answer:

All except the second one (angle g is not similar to angle r)

Step-by-step explanation:

Just look at the order of the letters. It it's the same, its similar.

4 0

3 years ago

What is Scatter Plots and Line of Best Fit in a summery

garri49 [273]

Answer:

Scatter plots are plots of data (different points on a plot). The line of best fit is the line that goes through the middle of the data so there are equal number of points on both sides of the line.

Step-by-step explanation:

8 0

3 years ago

Let X be the number of material anomalies occurring in a particular region of an aircraft gas-turbine disk. The article "Methodo

Shkiper50 [21]

Answer:

a) $P(X\leq 4)=0.0183+0.0733+ 0.1465+0.1954+0.1954=0.6288$

$P(X< 4)=P(X\leq 3)=0.0183+0.0733+ 0.1465+0.1954=0.4335$

b) $P(4\leq X\leq 8)=0.1954+0.1563+0.1042+0.0595+0.0298=0.5452$

c) $P(X \geq 8) = 1-P(X$

d) $P(4\leq X \leq 6)=0.1954+0.1563+0.1042=0.4559$

Step-by-step explanation:

Let X the random variable that represent the number of material anomalies occurring in a particular region of an aircraft gas-turbine disk. We know that $X \sim Poisson(\lambda=4)$

The probability mass function for the random variable is given by:

$f(x)=\frac{e^{-\lambda} \lambda^x}{x!} , x=0,1,2,3,4,...$

And f(x)=0 for other case.

For this distribution the expected value is the same parameter $\lambda$

$E(X)=\mu =\lambda=4$ , $Var(X)=\lambda=2$ , $Sd(X)=2$

a. Compute both P(X≤4) and P(X<4).

$P(X\leq 4)=P(X=0)+P(X=1)+ P(X=2)+P(X=3)+P(X=4)$

Using the pmf we can find the individual probabilities like this:

$P(X=0)=\frac{e^{-4} 4^0}{0!}=e^{-4}=0.0183$

$P(X=1)=\frac{e^{-4} 4^1}{1!}=0.0733$

$P(X=2)=\frac{e^{-4} 4^2}{2!}=0.1465$

$P(X=3)=\frac{e^{-4} 4^3}{3!}=0.1954$

$P(X=4)=\frac{e^{-4} 4^4}{4!}=0.1954$

$P(X\leq 4)=0.0183+0.0733+ 0.1465+0.1954+0.1954=0.9646$

$P(X< 4)=P(X\leq 3)=P(X=0)+P(X=1)+ P(X=2)+P(X=3)$

$P(X< 4)=P(X\leq 3)=0.0183+0.0733+ 0.1465+0.5311=0.7692$

b. Compute P(4≤X≤ 8).

$P(4\leq X\leq 8)=P(X=4)+P(X=5)+ P(X=6)+P(X=7)+P(X=8)$

$P(X=4)=\frac{e^{-4} 4^4}{4!}=0.1954$

$P(X=5)=\frac{e^{-4} 4^5}{5!}=0.1563$

$P(X=6)=\frac{e^{-4} 4^6}{6!}=0.1042$

$P(X=7)=\frac{e^{-4} 4^7}{7!}=0.0595$

$P(X=8)=\frac{e^{-4} 4^8}{8!}=0.0298$

$P(4\leq X\leq 8)=0.1954+0.1563+ 0.1042+0.0595+0.0298=0.5452$

c. Compute P(8≤ X).

$P(X \geq 8) = 1-P(X$

$P(X \geq 8) = 1-P(X$

d. What is the probability that the number of anomalies exceeds its mean value by no more than one standard deviation?

The mean is 4 and the deviation is 2, so we want this probability

$P(4\leq X \leq 6)=P(X=4)+P(X=5)+P(X=6)$

$P(X=4)=\frac{e^{-4} 4^4}{4!}=0.1954$

$P(X=5)=\frac{e^{-4} 4^5}{5!}=0.1563$

$P(X=6)=\frac{e^{-4} 4^6}{6!}=0.1042$

$P(4\leq X \leq 6)=0.1954+0.1563+0.1042=0.4559$

4 0

3 years ago

A woman has 21 total coins in her pocket, all of which are either dimes or quarters. If the total value of her change is $3.90,

Elza [17]

Answer with Step-by-step explanation:

Let there be d dimes and q quarters

A woman has 21 total coins in her pocket.

⇒ d+q=21 ------(1)

1 dime=$ 0.1

1 quarter=$ 0.25

The total value of her change is $3.90

⇒ 0.1d+0.25q=3.90

Multiplying both sides by 100,we get

10d+25q=390 --------(2)

(2)-10×(1)

10d+25q-10d-10q=390-210

15q=180

Dividing both sides by 15, we get

q=12

Putting value of q in (1),we get

d=9

Hence, Number of dimes=9

and number of quarters=12

Write the number of dimes, then the number of quarters separated by a comma.

9,12

8 0

3 years ago

Read 2 more answers