Question

Suppose a 125 N force is applied to a lawnmower handle at an angle of 35° with the ground and the lawnmower moves along the surface of the ground. If the lawnmower moves 56 m, how much work was done? (hint: use cos to find the x of force vector)

Answer 1

Answer:

Workdone is 5734.06Nm.

Explanation:

Given the following data;

Force applied = 125N

Angle = 35°

Distance = 56m

To find the workdone by the lawnmower, we would first of all find the horizontal component of the force applied.

$Horizontal force, Fx = mgCosd$

Where;

• Fx represents the horizontal force.

• m is the mass of an object.

• g is the acceleration due to gravity.

• d is the angle of inclination (theta).

mg = weight = 125N

Substituting into the equation, we have;

$Fx = 125 * Cos35$

$Fx = 125 * 0.8192$

Fx = 102.39N

Workdone is given by the formula;

$Workdone = force * distance$

$Workdone = 102.39 * 56$

Workdone = 5734.06Nm

Therefore, the work done by the lawnmower is 5734.06Nm.