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nata0808 [166]
3 years ago
8

Why is aluminum suitable material to use in makinv cans based on its physical and chemical properties

Physics
1 answer:
Llana [10]3 years ago
7 0

low density, malleable, easy to form into shapes, not very chem reactive

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A bus is traveling 25.0 km in 2 hours. What is the speed of the bus in millimeters per second?
trasher [3.6K]

Answer:

3472.222

Explanation:

In one hour, the bus travels at a 12.5 km. The speed is 12.5km/hr

Convert it to mm/s

And you get 3472.2mm/s

8 0
3 years ago
Help I'll mark brainliest
lubasha [3.4K]

Answer:

Animal 1 because it takes 3s to go 25 meters 3.5s to go 50 meters and 5s to go 75 meters while the others take longer.

Explanation:

4 0
3 years ago
A cylinder with rotational inertia I1=2.0kg·m2 rotates clockwise about a vertical axis through its center with angular speed ω1=
Mrac [35]

Answer:

<em>a) 0.67 rad/sec in the clockwise direction.</em>

<em>b) 98.8% of the kinetic energy is lost.</em>

Explanation:

Let us take clockwise angular speed as +ve

For first cylinder

rotational inertia I = 2.0 kg-m^2

angular speed ω = +5.0 rad/s

For second cylinder

rotational inertia I = 1.0 kg-m^2

angular speed = -8.0 rad/s

The rotational momentum of a rotating body is given as = Iω

where I is the rotational inertia

ω is the angular speed

The rotational momenta of the cylinders are:

for first cylinder = Iω = 2.0 x 5.0 = 10 kg-m^2 rad/s

for second cylinder = Iω = 1.0 x (-8.0) = -8 kg-m^2 rad/s

The total initial angular momentum of this system cylinders before they were coupled together = 10 + (-8) = <em>2 kg-m^2 rad/s</em>

When they are coupled coupled together, their total rotational inertia I_{t} = 1.0 + 2.0 = 3 kg-m^2

Their final angular rotational momentum after coupling = I_{t}w_{f}

where I_{t} is their total rotational inertia

w_{f} = their final angular speed together

Final angular momentum = 3 x w_{f} = 3w_{f}

According to the conservation of angular momentum, the initial rotational momentum must be equal to the final rotational momentum

this means that

2 =  3w_{f}

w_{f} = final total angular speed of the coupled cylinders = 2/3 = <em>0.67 rad/s</em>

From the first statement, <em>the direction is clockwise</em>

b) Rotational kinetic energy = \frac{1}{2} Iw^{2}

where I is the rotational inertia

w is the angular speed

The kinetic energy of the cylinders are:

for first cylinder = \frac{1}{2} Iw^{2} = \frac{1}{2}*2*5^{2} = 25 J

for second cylinder = \frac{1}{2}*1*8^{2} = 32 J

Total initial energy of the system = 25 + 32 = 57 J

The final kinetic energy of the cylinders after coupling = \frac{1}{2}I_{t}w^{2} _{f}

where

where I_{t} is the total rotational inertia of the cylinders

w_{f} is final total angular speed of the coupled cylinders

Final kinetic energy =  \frac{1}{2}*3*0.67^{2} = 0.67 J

kinetic energy lost = 57 - 0.67 = 56.33 J

percentage = 56.33/57 x 100% = <em>98.8%</em>

6 0
3 years ago
Three resistors are connected in series to a 42.1 V battery: R1 = 2.96 Ω, R2 = 7.48 Ω and R3 = 7.42 Ω. Now, as R3 heats up, its
LuckyWell [14K]

Answer:

dP/dt = 26.12 W/s

Explanation:

First, we need to find the value of dt at the instant when R₃ becomes 91.7 Ω. Therefore, we use:

dR₃/dt = 0.552 Ω/s

where,

dR₃ = Change in value of resistance 3 = 91.7 Ω - 7.42 Ω = 84.28 Ω

dt = time interval = ?

Therefore,

84.28 Ω = (0.552 Ω/s)(dt)

dt = (84.28 Ω)/(0.552 Ω/s)

dt = 152.68 s

Now, we find change in power (dP):

dP = V(R₁ + R₂ + dR₃)

dP = (42.1 V)(2.96 Ω + 7.48 Ω + 84.28 Ω)

dP = 3987.71 W

Dividing by dt:

dP/dt = 3987.71 W/152.68 s

<u>dP/dt = 26.12 W/s</u>

7 0
4 years ago
1. The inlet section of a vacuum cleaner is a rectangle, 1 in by 5 in. The blower is able to provide suction at 25 cubic feet pe
adoni [48]

Answer:

average velocity at the inlet = 3.66 m/s

Explanation:

given data

discharge Q =  25 ft³ /min = \frac{25}{60}  = 0.417 ft³  

vacuum cleaner = 1 in by 5 in = \frac{1}{12} \ by\   \frac{5}{12}   ft

solution

we know discharge that is express as

Q = Area × Velocity   .............1

put here value and we will get  average velocity at the inlet

average velocity at the inlet = \frac{0.417}{\frac{1}{12} \frac{5}{12} }  

average velocity at the inlet = 3.66 m/s

7 0
3 years ago
Read 2 more answers
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