PQRS is a parallelogram Given
SR=PQ property of parallelogram
m∠S=m∠Q property of parallelogram
SP=QR property of parallelogram
XP=RY given
SP-XP=QR-RY substitution
SX=QY segment subtraction
ΔSRX is conggruent to ΔQPY SAS theorem (side-angle-side)
XR=YP CPCTC (corresponding parts of congruent triangles are congruent)
Answer:
yes
Step-by-step explanation:
y(x) is even or odd according as y(−x)=±y(x) . Here, #y(-x)=-(-x)^3=-(-x^3)=x^3=-y(x). So, y is an odd function of x.
Answer:
f(10) = 13
Step-by-step explanation:
f(x) = x/2 + 8
Let x = 10
f(10) = 10/2 +8
f(10) = 5+8
f(10) = 13
Answer:
The answer to the equation from question 7 is 14.
Step-by-step explanation:
In question 7, we are given an equation.
2³ + (8 - 5)² - 3
First, subtract 5 from 8 in the parentheses.
2³ + 3² - 3
Next, solve the exponents for 2³ and 3².
8 + 9 - 3
Add 8 to 9.
17 - 3
Subtract 3 from 17.
14
So, the answer to this equation from question 7 is 14.
