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3 years ago

what is the following product of assume Y is greater than or equal to 0 square root y to the third Times Square Root why 2/3

Mathematics

1 answer:

sattari [20]3 years ago

4 0

Step-by-step explanation:

$\sqrt{y3} \times \sqrt{y3}$

$\sqrt{y3 \times y3}$

$\sqrt{y3 + 3}$

$\sqrt{y6}$

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If the angles of a quadrilateral are 140, 80, 60, 80 then what type of quadrilateral could it be?

Lubov Fominskaja [6]

Im sorry but, a friend told it was a rectangle, im sure if thats a good enough answer but if it isn't im sorry

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3 years ago

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Pete walks 6 miles during each trip to school. How many trips does he need to make in order to make in a total of 48 miles?

Diano4ka-milaya [45]

Answer:

8 trips

Step-by-step explanation:

ALl you have to do is divide 48 by 6, which will give you 8, and there's your answer!

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3 years ago

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Write an equation for the circle with endpoints of a diameter (9, 4) and (-3, -2)

inysia [295]

If the diameter is at (9,4) and (-3,-2), then the center of the circle is the midpoint of that segment.

and since we know that the radius of a circle is half of the diameter, whatever long that diameter segment is, the radius is half that.

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points }
\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~ 9 &,& 4~) 
% (c,d)
&&(~ -3 &,& -2~)
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{ x_2 + x_1}{2}\quad ,\quad \cfrac{ y_2 + y_1}{2} \right)
\\\\\\
\left( \cfrac{-3+9}{2}~~,~~\cfrac{-2+4}{2} \right)\implies \stackrel{center}{(3~,~1)}$

$\bf -------------------------------\\\\
~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~ 9 &,& 4~) 
% (c,d)
&&(~ -3 &,& -2~)
\end{array}
\\\\\\
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
d=\sqrt{(-3-9)^2+(-2-4)^2}\implies d=\sqrt{(-12)^2+(-6)^2}
\\\\\\
d=\sqrt{180}\qquad \qquad \qquad radius=\cfrac{\sqrt{180}}{2}$

$\bf -------------------------------\\\\
\textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{3}{ h},\stackrel{1}{ k})\qquad \qquad 
radius=\stackrel{\frac{\sqrt{180}}{2}}{ r}
\\\\\\
(x-3)^2+(y-1)^2=\left( \frac{\sqrt{180}}{2} \right)^2\implies (x-3)^2+(y-1)^2=\cfrac{(\sqrt{180})^2}{2^2}
\\\\\\
(x-3)^2+(y-1)^2=\cfrac{180}{4}\implies (x-3)^2+(y-1)^2=45$

7 0

3 years ago

Find all numbers whose absolute value is -5.

Kryger [21]

There are none. Absolute values are always positive

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3 years ago

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Car park algebra question

Svetllana [295]

You did south, north, correctly

but last one

twice north is 2 times (x+48) or 2x+96

so

s=x
n=x+48
c=4x
s+c>2x+96
subsitute s for x and 4x for c
x+4x>2x+96
5x>2x+96
minus 2x both sides
3x>96
divide both sides by 3
x>32
it cannot be equal to 32 so
the minimum value is 33 spaces in south car park

5 0

3 years ago

what is the following product of assume Y is greater than or equal to 0 square root y to the third Times Square Root why 2/3​

what is the following product of assume Y is greater than or equal to 0 square root y to the third Times Square Root why 2/3