48.3 g AgNO3 / 169.9 g/mol = 0.284 moles AgNO3
0.284 mol AgNO3 X (1 mol Ag2CrO4/2 mol AgNO3) = 0.142 mol Ag2CrO4
0.142 mol Ag2CrO4 X 331.7 g/mol = 47.1 g Ag2CrO4
Answer:
Mass is the amount of matter in an object and does not change with location.
Explanation:
Answer:
he major types of connective tissue are connective tissue proper, supportive tissue, and fluid tissue. Loose connective tissue proper includes adipose tissue, areolar tissue, and reticular tissue.
Explanation:
Answer: There are
molecules present in 7.62 L of
at
and 722 torr.
Explanation:
Given : Volume = 7.62 L
Temperature = 
Pressure = 722 torr
1 torr = 0.00131579
Converting torr into atm as follows.

Therefore, using the ideal gas equation the number of moles are calculated as follows.
PV = nRT
where,
P = pressure
V = volume
n = number of moles
R = gas constant = 0.0821 L atm/mol K
T = temperature
Substitute the values into above formula as follows.

According to the mole concept, 1 mole of every substance contains
atoms. Hence, number of atoms or molecules present in 0.244 mol are calculated as follows.

Thus, we can conclude that there are
molecules present in 7.62 L of
at
and 722 torr.