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Zinaida [17]
3 years ago
5

Balance the following reaction. As2S3 + 9O2 → 2As2O3 + SO2

Chemistry
2 answers:
kumpel [21]3 years ago
8 0

Answer:

2As2S3 + 9O2 = 2As2O3 + 6SO2

Explanation:

Reil [10]3 years ago
3 0

Answer:

First option is (2) and second option is (6)

Explanation: (2) , (6) odyssey !

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Aqueous lithium sulfate was mixed with aqueous strontium chlorate, and a crystallized strontium sulfate product was formed. cons
Dmitriy789 [7]

Lithium sulfate is Li2SO4

Strontium chlorate is Sr(ClO3)2

Strontium sulfate is SrSO4

 

So the complete balanced chemical reaction for this is:

 

Li2SO4 (aq) +  Sr(ClO3)2 (aq) -->  SrSO4 (s)  +  2 LiClO3 (aq)

 

 

This is a type of double replacement reaction since there is an exchange of ions.

4 0
3 years ago
Heat moves from what source by convection and radiation?
Alona [7]

Answer:

heat can move from any source but if we are being legitimate it moves from convection

Explanation:

8 0
3 years ago
What percentage of the earth is water?
OleMash [197]

Answer:

approximately 71%

4 0
3 years ago
Read 2 more answers
Pls help fast, I will give brainliest!
beks73 [17]

Answer:

c

Explanation:

4 0
3 years ago
A 5.76 liter sample of a gas at 22.00C mL 748 torr pressure was heated to a final volume of 17.28 liters, with the pressure rema
timama [110]

Answer:

The final temperature was 612 °C

Explanation:

Charles's law relates the volume and temperature of a certain amount of ideal gas, maintained at a constant pressure, using a constant of direct proportionality. In this law, Charles says that at constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases. That is, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the ratio between volume and temperature will always have the same value:

\frac{V}{T}=k

When you want to study two different states, an initial and a final one of a gas and evaluate the change in volume as a function of temperature or vice versa, you can use the expression:

\frac{V1}{T1} =\frac{V2}{T2}

In this case:

  • V1= 5.76 L
  • T1= 22 °C= 295 °K (Being 0°C=273°K)
  • V2=17.28 L
  • T2=?

Replacing:

\frac{5.76 L}{295 K} =\frac{17.28 L}{T2}

Solving:

T2 =\frac{17.28 L}{\frac{5.76 L}{295 K}}=\frac{17.28 L*295 K}{5.76 L}

T2= 885 °K = 612 °C

<u><em>The final temperature was 612 °C</em></u>

5 0
3 years ago
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