Answer:
300,000,000 and the second question is the same.
Explanation:
Edge
Complete question:
How many x-ray photons per second are created by an x-ray tube that produces a flux of x rays having a power of 1.00 W. Assume the average energy per photon in 78.0 keV.
Answer:
The number of x-ray photons per second created by the x-ray tube is 8.01 x 10¹³ photons/sec
Explanation:
Given;
power of the flux produced, P = 1 W = 1 J/s
energy per photon, E = 78 keV
Convert the energy per photon to J
E = 78 x 10³ x 1.6 x 10⁻¹⁹ = 1.248 x 10⁻¹⁴ J / photon
let the number of photons = n
n(1.248 x 10⁻¹⁴ J / photon) = 1 J/s

Therefore, the number of x-ray photons per second created by the x-ray tube is 8.01 x 10¹³ photons/sec
Answer:
1.) Total distance = 70 m
2.) Total displacement = +30m
Explanation:
Distance is a scaler quantity. That is, we will be concerned about its magnitude only and not direction.
Total distance = 10 + 20 + 40 = 70 m
While displacement is a vector quantity. We will consider both the magnitude and its direction.
Forward direction will be positive while backward direction will be negative
Total displacement = +10 - 20 + 40
Total displacement = +30 m
Answer:
Explanation:
Coulomb's law states that the force of attraction or repulsion between any two charges is proportional to the product of the magnitude of charges and inversely proportional to the square of the distance between the charges
⇒
∴
where
is the force of attraction or repulsion
is Coulumb's constant=
and
are the magnitude of the charges
is the distance between two charges
The force between the two charges is attractive if they are of different polarity
The force between the two charges is repulsive if they are of same polarity
Question 7:
Given:
, 
By coulomb's law,

⇒
Question 6:
Given:
, 
By coulomb's law,

⇒
¿Es esta una pregunta verdadera o falsa? Por cierto, no hay mucha gente que hable español en esta aplicación, así que buena suerte.