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Luda [366]
2 years ago
8

what causes you to get warm if you stand bear a fire ? A . Transmission B . Radiation C . Convection D . Conduction​

Physics
2 answers:
stira [4]2 years ago
5 0

Answer:

B

Explaination:

Radiation refers to the emission of energy in rays or waves. Heat moves through space as energy waves.

enot [183]2 years ago
3 0

Answer:

Radiation

Explanation:

Heat can be transferred though thin air

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Physics is confusing :(
Ket [755]

Answer:

30's-40's

Explanation:

4 0
3 years ago
A sophomore with nothing better to do adds heat to a mass 0.300 kg of ice at 0.0 âc until it is all melted.
kramer
Melting ice?  Man, that's cold
8 0
3 years ago
Which equation states Newton's second law?
Delicious77 [7]

Answer:

It's actually

F=ma

Force=Mass x Acceleration

So...when we inverse it..

It becomes:

B. a= F/m

5 0
3 years ago
To push a 26.0 kg crate up a frictionless incline, angled at 25.0° to the horizontal, a worker exerts a force of 209 N parallel
alukav5142 [94]

Answer:

(a) W = +397.1 J

(b) W = -204.6 J

(c) W = 0

(d) W= + 192.5 J

Explanation:

Work (W) is defined as the product of force (F) by the distance (d)the body travels due to this force. :

W= F*d Formula ( 1)

The forces that perform work on an object must be parallel to its displacement.

The forces perpendicular to the displacement of an object do not perform work on it.

The work is positive (W+) if the force has the same direction of movement of the object.  

The work is negative (W-) if the force has the opposite direction of the movement of the object.

Problem development

(a) Work performed by the worker's applied force on the box .

W= 209 N * 1.9 m = +397.1 J

(b) Work performed by the gravitational force on the crate

We calculate the weight component parallel to the displacement of the box:

We define the x-axis in the direction of the inclined plane ,25.0° to the horizontal.

We define the y-axis and in the direction of the plane perpendicular to the inclined plane.

W= m*g=26*9.8= 254.8N : total box weight

Wx= W*sen25.0°= 254.8*sen25.0°= 107.68 N

W = -Wx *d =107.68 N *1.9 m= -204.6 J

(c) Work performed by normal force (N) exerted by the incline on the crate

The force N is perpendicular to the displacement, then:

W=0

(d) Total work done on the crate

W = 397.1 J -204.6 J

W = 192.5 J

4 0
3 years ago
A rock is dropped from rest and falls 50 m determine the velocity upon hitting the groung?
LekaFEV [45]
V^2= 2* g * s
V^2 = 2 * 9.8 * 50 = 980
v = square root (980)=...... m/s
7 0
3 years ago
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