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Luda [366]
3 years ago
8

what causes you to get warm if you stand bear a fire ? A . Transmission B . Radiation C . Convection D . Conduction​

Physics
2 answers:
stira [4]3 years ago
5 0

Answer:

B

Explaination:

Radiation refers to the emission of energy in rays or waves. Heat moves through space as energy waves.

enot [183]3 years ago
3 0

Answer:

Radiation

Explanation:

Heat can be transferred though thin air

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a bicycle rider pedals towards a hill at a speed of 7.5w/s. the combined mass of the bicycle and the rider is 75.0kg the cycle a
siniylev [52]

Answer:

2.8125 meters

Explanation:

I will assume 7.5 m/s

When the Kinetic Energy is entirely converted to Potential energy the max height will have been reached

KE = PE

1/2 m v^2 = mgh     divide by m

1/2 v^2 = gh         looking for  h     so divide both sides by

1/2 v^2 / g   = h      sub in the values   using g = 10 m/s^2

1/2 ( 7.5 )^2 / 10  = 2.8125 m

4 0
2 years ago
the hot gas lines need to be insulated? A never B always C if they are exposed to cold temperatures that could cause the refrige
muminat
The answer is a because it never needs to be insulated
8 0
3 years ago
I'm spending 98 points please help!
juin [17]

Answer: C. 8.0 m west

Explanation: The arrows are going 15 m west and 7.0 m east. 7 meters of the west will cancel out because 15-7=8. Subtract the smaller number from the bigger number, which is west minus east. The answer will be 8.0 m west.

5 0
4 years ago
Read 2 more answers
A ball starts to roll up a slope with a slope with a velocity of 5m/s and comes to a stop after rolling 5.0m up the slope. Assum
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8 0
3 years ago
An object at rest on a flat, horizontal surface explodes into two fragments, one seven times as massive as the other. The heavie
IgorLugansk [536]

Answer:

The distance the lighter fragments slides is 343 m

Explanation:

Here, we have

Let the mass of the heavier fragments be m₁

Let the distance the heavy object slide be d₁

Let the mass of the lighter fragments be m₂

Let the final velocity of the heavier fragments be v₁

Let the final velocity of the lighter fragments be v₂

Let the distance the light object slide be d₂

The distance traveled by  the heavy fragment = 7.00 m

Therefore since m₁ = 7 × m₂ we have

Initial total momentum = final total momentum

Since the initial total momentum = 0 we have

m₁·v₁ + m₂·v₂ = 0  or

7·m₂·v₁  = -m₂·v₂

∴ v₂ = 7·v₁

The net work done by the heavier block is

W_{net, 7m} = μk × m₁ × g × d₁ = 1/2×m₂×v₂²

Also v₁² = 2μk·g·d₁ and

v₂² = 2μk·g·d₂ so that since v₂ =  7·v₁ or v₁ = v₂/7 we get

(v₂/7)² = 2μk·g·d₁

So v₂²/49 = 2μk·g·d₁

or (2μk·g·d₂)/49 = 2μk·g·d₁

∴ d₂/49 = d₁

d₂ = d₁×49 = 7 × 49 = 343 m

The distance the lighter fragments slides = 343 m.

7 0
3 years ago
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