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Aleks04 [339]
3 years ago
9

At a certain elevation, the pilot of a balloon has a mass of 120 lb and a weight of 119 lbf. What is the local acceleration of g

ravity, in ft/s2, at that elevation
Physics
1 answer:
Strike441 [17]3 years ago
3 0

Answer:

31.905 ft/s²

Explanation:

Given that

Mass of the pilot, m = 120 lb

Weight of the pilot, w = 119 lbf

Acceleration due to gravity, g = 32.05 ft/s²

Local acceleration of gravity of found by using the relation

Weight in lbf = Mass in lb * (local acceleration/32.174 lbft/s²)

119 = 120 * a/32. 174

119 * 32.174 = 120a

a = 3828.706 / 120

a = 31.905 ft/s²

Therefore, the local acceleration due to gravity at that elevation is 31.905 ft/s²

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Hence, the correct option is (A) "destructive interference"

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The rotating blade of a blender turns with constant angular acceleration of 1.51 rad/s^2. How much time does it take to reach an
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time to reach an angular velocity of 36.8 is 24.370 s.

<h3></h3><h3>What is angular acceleration?</h3>

The temporal rate at which angular velocity changes is referred to as angular acceleration. Naturally, there are two forms of angular acceleration, referred to as spin angular acceleration and orbital angular acceleration, just as there are two types of angular velocity, namely spin angular velocity and orbital angular velocity. As opposed to orbital angular acceleration, which is the angular acceleration of a point particle around a fixed origin, spin angular acceleration describes the angular acceleration of a rigid body about its centre of rotation.

w(t) = w(0) + α*t

also w(0) =0

=> time = 36.8/1.51= 24.370 s

to learn more about angular acceleration go to - brainly.com/question/21278452

#SPJ4

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