Answer:
2.771208%
Explanation:
= Change of volume
= Initial volume
= Change in temperature = (0.3-1050)
= Volumetric coefficient of thermal expansion = ![-26.4\times 10^{-6}\ /K](https://tex.z-dn.net/?f=-26.4%5Ctimes%2010%5E%7B-6%7D%5C%20%2FK)
Volumetric expansion of heat is given by
![\frac{\Delta V}{V_0}=\beta \Delta T\\\Rightarrow \frac{\Delta V}{V_0}=-26.4\times 10^{-6}\times (0.3-1050)\\\Rightarrow \frac{\Delta V}{V_0}=0.02771208](https://tex.z-dn.net/?f=%5Cfrac%7B%5CDelta%20V%7D%7BV_0%7D%3D%5Cbeta%20%5CDelta%20T%5C%5C%5CRightarrow%20%5Cfrac%7B%5CDelta%20V%7D%7BV_0%7D%3D-26.4%5Ctimes%2010%5E%7B-6%7D%5Ctimes%20%280.3-1050%29%5C%5C%5CRightarrow%20%5Cfrac%7B%5CDelta%20V%7D%7BV_0%7D%3D0.02771208)
Finding percentage
![\frac{\Delta V}{V_0}=0.02771208\times 100=2.771208\%](https://tex.z-dn.net/?f=%5Cfrac%7B%5CDelta%20V%7D%7BV_0%7D%3D0.02771208%5Ctimes%20100%3D2.771208%5C%25)
The ratio of change of volume to initial volume is 2.771208%
Answer:
Ball
Explanation:
We can set a system of equations for the objects and the systems:
![Ug_{1}=18g\\](https://tex.z-dn.net/?f=Ug_%7B1%7D%3D18g%5C%5C)
The density of water is 1kg/liter, therefore
![Ug_{2}=(2*1)*8g\\\\Ug_{2}=16g\\](https://tex.z-dn.net/?f=Ug_%7B2%7D%3D%282%2A1%29%2A8g%5C%5C%5C%5CUg_%7B2%7D%3D16g%5C%5C)
Compare Ug1 to Ug2:
![Ug_{1} > Ug_{2}](https://tex.z-dn.net/?f=Ug_%7B1%7D%20%3E%20Ug_%7B2%7D)
Intensity is the word you are looking for!
How do you ask a question but don’t know the answer we will never know
Pressure, P = Force, F/ Surface Area, A
In the current scenario,
Force, F = Weight = mg = 1/1000*9.81 = 9.81*10^-3 N
Surface area, A = πr^2 = π*(0.210/1000)^2 = 1.385*10^-7 m^2
Therefore,
P = F/A = (9.81*10^-3)/(1.385*10^-7) = 70,807.71 N/m^2