The image shows the electric field lines around two charged particles.

Physics

2 answers:

DENIUS [597]3 years ago

8 0

It's either 3 or 4 I know this becuase I have read a book about electricity

Andrew [12]3 years ago

8 0

Answer:

D. 4

Explanation:

The electric force will be maximum at the position where the number of electric lines are maximum. As we can observe that the maximum number of lines are at position 4.

Thus, electric force is maximum at 4.

You might be interested in

Which type of force can be in the same it opposite direction?

LuckyWell [14K]

Answer:

C) unbalanced

Explanation:

Equal forces acting in opposite directions are called balanced forces. Balanced forces acting on an object will not change the object's motion. When you add equal forces in opposite direction, the net force is zero.

4 0

3 years ago

What is the approximate size of Earth’s magnetic field? Where are Earth’s magnetic poles? Where is the magnet that causes Earth’

nataly862011 [7]

Earths poles are on opposite sides of the earth

7 0

3 years ago

Read 2 more answers

Identify three specific situations in which machines make work easier.

Komok [63]

Construction, like building a home/building, digging, like in a mine, and opening a soda can, where the part to open is a lever.

5 0

3 years ago

A 1.00 kg particle has the xy coordinates (-1.20 m, 0.500 m) and a 4.50 kg particle has the xy coordinates (0.600 m, -0.750 m).

just olya [345]

Answer:

a) The x coordinate of the third mass is -1.562 meters.

b) The y coordinate of the third mass is -0.944 meters.

Explanation:

The center of mass of a system of particles ( $\vec r_{cm}$ ), measured in meters, is defined by this weighted average:

$\vec r_{cm} = \frac{\Sigma_{i=1}^{n}\,m_{i}\cdot \vec r_{i}}{\Sigma_{i=1}^{n}\,m_{i}}$ (1)

Where:

$m_{i}$ - Mass of the i-th particle, measured in kilograms.

$\vec r_{i}$ - Location of the i-th particle with respect to origin, measured in meters.

If we know that $\vec r_{cm} = (-0.500\,m,-0.700\,m)$ , $m_{1} = 1\,kg$ , $\vec r_{1} = (-1.20\,m, 0.500\,m)$ , $m_{2} = 4.50\,kg$ , $\vec r_{2} = (0.600\,m, -0.750\,m)$ and $m_{3} = 4\,kg$ , then the coordinates of the third particle are: