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Rainbow [258]
2 years ago
6

Can we see the back side of the moon from earth?

Physics
2 answers:
AVprozaik [17]2 years ago
6 0
No, since the earth is always rotating around the same time as earth we can’t see the other side of the moon
Olegator [25]2 years ago
5 0

No. The moon always keeps the same side facing us. Its rotation and revolution periods are equal.

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Calculate the equivalent of 20 degrees Celsius in degrees Fahrenheit and Kelvin.
alekssr [168]

Answer:

68 °F, 293.15 K

Explanation:

Fahrenheit, Kelvin and Celsius are the different scales of temperature in which temperature is measured.

Given : T = 20°C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

<u>T = (20 + 273.15) K = 293.15 K </u>

The conversion of T( °C) to T(F) is shown below:

T (°F) = (T (°C) × 9/5) + 32

So,

<u>T (°F) = (20 × 9/5) + 32 = 68 °F</u>

3 0
3 years ago
Jenny wanted to test whether worms prefer light or darkness best. After
myrzilka [38]

Answer:

True

Explanation:

An independent variable is the variable that is changed or controlled in a scientific experiment to test the effects on the dependent variable. You are changing light or dark

3 0
3 years ago
Bernie drove home from a vacation in 1.5 hours. He traveled a total distance of 60 miles. What was his average speed in miles pe
mafiozo [28]

Answer: 40

Explanation:

I believe this is correct. I did 60/1.5 to get 40/mph

6 0
3 years ago
Read 2 more answers
A. Draw four rays parallel to the optical axis of your mirror. Two above the optic axis and two below it.
Katen [24]

Answer:

   f = q

Explanation:

In the attachment we can see a diagram of the parallel rays.

The dotted line represents the normal to the mirror surface

These rays when reflected using the constructor equation

        \frac{1}{f} = \frac{1}{p} + \frac{1}{q}

where p and q are the distance to the object and the image respectively.

Since the rays are parallel P = inf

          1 / f = 1 / inf + 1 / q

          f = q

this means that all the rays focus on one focal point.

6 0
2 years ago
A billiard ball moving at 0.5 m/s strikes another identical billiard ball, which is at rest, in an elastic head-on collision on
NikAS [45]

Answer: assuming that the billiard balls are of identical weight the impacted billiard ball will move forward at around 0.5m/s (not considering energy conservation). The ball impacting the 2nd one would stop because most of its Kinetic energy would have been transferred into the not moving ball.

Explanation: hope this helps!

4 0
3 years ago
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