The total number of cookies baked by grandma = 96
Number of grandchildren = 8
As given, all cookies were evenly divided among 8 children, let us assume that everyone except Cindy got equal share. So on being divided equally, it becomes, 
cookies per children.
But, as mentioned that Cindy received 'c' cookies less, so let us suppose Cindy received 'x' cookies.
Expression becomes: 
Hence, Cindy received 12-c cookies.
Hey there!
If the price per orange is $.26 and we want to know how many oranges he bought and we have our total, we can set o equal to how many oranges he got and set up an algebraic equation:
0.26o = 2.08
We multiply .26 by o because o is how many oranges he bought and that's what we're solving for- so we multiply by the unit price.
To isolate o, we divide both sides by .26 to get:
The answer is C- Jim bought 8 oranges.
Hope this helps!
First, you have to set a system of equations to determine the number of fiction and of nonfiction books.Call f the number of fiction books and n the number of nonfiction books. Then 400 = f + n. And f = n + 40 => n = f - 40 => 400 = f + f - 40 => 400 - 40 = 2f => f = 360 / 2 = 180. Now to find the probability of picking two fiction books, take into account the the Audrey will pick from 180 fiction books out of 400, and Ryan will pick from 179 fiction books out of 399, so the probability will be<span> (180/ 400) * (179/399) = 0.20 (rounded to two decimals). Answer: 0.20</span>
Step-by-step explanation:
hope this helps theirs 3 pictures
Answer:
60 mph
Step-by-step explanation:
Given;
Total distance covered d = 440 miles
Average speed in the first 4 hours v1 = 50 mph
Total time taken for the whole trip t = 8:00 to 4:00pm
t = 16:00-8:00 = 8 hours
Firstly we need to calculate the distance covered during the first 4 hours;
d1 = average speed × time = v1 × t1
t1 = 4
d1 = 50 × 4 = 200 miles
Then we need to calculate the distance covered in the second period of the journey;
d = d1 + d2
d2 = d - d1
Substituting the values;
d2 = 440 - 200
d2 = 240 miles
The time taken for the second period of travel t2;
t2 = t -t1 = 8-4
t2 = 4 hours
Average speed = distance travelled ÷ time taken
The average speed for the second part of the trip v2 is;
v2 = d2 ÷ t2
Substituting t2 and d2;
v2 = 240 miles ÷ 4 hours
v2 = 60 mph
The average speed during the second part of the trip is 60 mph
