Find the absolute maximum of m(t)=t^3-12t^2-144t and justify your answer
1 answer:
Answer:
Step-by-step explanation:
m(t)=t³-12t²-144t
Take the derivative of t:
t'=3t²-24t-144
Set it to 0:
3t²-24t-144=0
Solve for t:
t²-8t-48=0
(t-12)(t+4)=0
t=12 or -4
On a graph, you'll find that the maximum value occurs at t=-4 ..............
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Step-by-step explanation:
Answer:
a) 
b) 
c) 
d) E(3X + 2) = 21.35
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Step-by-step explanation:
a) 
b)
c)
d)
e)
f)
g)
h)
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