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Elodia [21]
3 years ago
9

When 3(2x-5) is added to 2(4-x) the result is

Mathematics
1 answer:
enyata [817]3 years ago
7 0
Hello,

3(2x-5)+2(4-x)
=6x-15+8-2x
=4x-7

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A radio station is giving away concert tickets to every 60th collar and a concert T-shirt to every 45th color what will be the n
Ludmilka [50]

Answer:

180th caller

Step-by-step explanation:

45 * 4 = 180

60 * 3 = 180

180 is the LCM

6 0
2 years ago
Three consecutive integers have a sum of 42. find the integers.
ioda
The answer is 13,14,15.
6 0
3 years ago
Which properties are present in a table that represents an exponential function in the form y-b* when b > 1?
erastovalidia [21]

Answer:

<u>Properties that are present are </u>

Property I

Property IV

Step-by-step explanation:

The function given is  y=b^x  where b > 1

Let's take a function, for example,  y=2^x

Let's check the conditions:

I. As the x-values increase, the y-values increase.

Let's put some values:

y = 2 ^ 1

y = 2

and

y = 2 ^ 2

y = 4

So this is TRUE.

II. The point (1,0) exists in the table.

Let's put 1 into x and see if it gives us 0

y = 2 ^ 1

y = 2

So this is FALSE.

III. As the x-value increase, the y-value decrease.

We have already seen that as x increase, y also increase in part I.

So this is FALSE.

IV. as the x value decrease the y values decrease approaching a singular value.

THe exponential function of this form NEVER goes to 0 and is NEVER negative. So as x decreases, y also decrease and approached a value (that is 0) but never becomes 0.

This is TRUE.

Option I and Option IV are true.

3 0
3 years ago
Read 2 more answers
Determine if x + 2 is a factor of p(x) = x 4 + 3x 3 + 4x 2 - 8 and explain why.
Andrej [43]
The Factor Theorem says (x - a) is a factor of function p(x) if p(a)=0

so check for p(-2)

= -2^4 +3(-2)^3 + 4(-2)^2 - 8

= 16 - 24 +16 -8

= 0

so (x + 2) is a factor
3 0
2 years ago
Which of the followings explains the difference between a regular subquery and a correlated subquery?
Fynjy0 [20]
Correlated means that they relate so probably this might help
5 0
3 years ago
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