Jeremy can choose his outfit in following ways:
2 ways to select a shirt
2 ways to select a pant
2 ways to select socks
3 ways to select the footwear.
Total number of ways to select the dress = 2 x 2 x 2 x 3 = 24 ways
Jeremy will select an outfit that includes flip-flops, argyle socks and denim pants. The shirt is not specified, so the shirt can be any.
So there are 2 ways to select a shirt, 1 way to select the pant, socks and footwear. So Jeremy can select the desired outfit in 2 ways.
Thus, the probability that Jeremy will select an outfit that includes flip-flops, argyle socks and denim pants = 2/24 = 1/12
The answer is 1/3 chances, There are 12 tables in total, 4 red and 8 blue. You can Render that down to 1 red and 2 blue, now there are 3 tables and only 1 is red, therefore the answer is 1/3 chance
When you solve that you get 30.825 because you divided 123.3 which was your dimensions times 9 and if you divide that by 4 you get 30.825 . Let me know if that is correct if not I will find new solution!
