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2 years ago

5

A baseball bat is a lever. Which of the following explains how a baseball bat differs from a lever like a pry bar?

1 answer:

Gnesinka [82]2 years ago

6 0

Complete question is;

A baseball bat is a lever. Which of the following explains how a baseball bat differs from a lever like a pry bar?

A) In a baseball bat, effort force is smaller and is applied over a large distance, while the resistance force is smaller and is applied over a long distance.

B) In a baseball bat, effort force is smaller and is applied over a large distance, while the resistance force is smaller and is applied over a short distance.

C) In a baseball bat, effort force is larger and is applied over a short distance, while the resistance force is smaller and is applied over a long distance.

D) In a baseball bat, effort force is larger and is applied over a short distance, while the resistance force is smaller and is applied over a short distance.

Answer:

C) In a baseball bat, effort force is larger and is applied over a short distance, while the resistance force is smaller and is applied over a long distance.

Explanation:

The correct answer is option C. This is because unlike in a pry bar, the effort force when swinging a baseball bat is larger and it is applied over a short distance; and in return the resisting force is smaller and it's applied over a long distance.

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A vector always consits of

Kazeer [188]

Answer:

Size and Direction

Explanation:

8 0

3 years ago

Read each question carefully. Show all your work for each part of the question. The parts within the question may not have equal

kirza4 [7]

At t =0, the velocity of A is greater than the velocity of B.

We are told in the question that the spacecrafts fly parallel to each other and that for the both spacecrafts, the velocities are described as follows;

A: vA (t) = ť^2 – 5t + 20

B: vB (t) = t^2+ 3t + 10

Given that t = 0 in both cases;

vA (0) = 0^2 – 5(0) + 20

vA = 20 m/s

For vB

vB (0) = 0^2+ 3(0) + 10

vB = 10 m/s

We can see that at t =0, the velocity of A is greater than the velocity of B.

Learn more: brainly.com/question/24857760

Read each question carefully. Show all your work for each part of the question. The parts within the question may not have equal weight. Spacecrafts A and B are flying parallel to each other through space and are next to each other at time t= 0. For the interval 0 <t< 6 s, spacecraft A's velocity v A and spacecraft B's velocity vB as functions of t are given by the equations va (t) = ť^2 – 5t + 20 and VB (t) = t^2+ 3t + 10, respectively, where both velocities are in units of meters per second. At t = 6 s, the spacecrafts both turn off their engines and travel at a constant speed. (a) At t = 0, is the speed of spacecraft A greater than, less than, or equal to the speed of spacecraft B?

3 0

2 years ago

An ideal spring is mounted horizontally, with its left end fixed. The force constant of the spring is 170 N/m. A glider of mass

gizmo_the_mogwai [7]

Answer:

Explanation:

First of all we shall find the velocity at equilibrium point of mass 1.2 kg .

It will be ω A , where ω is angular frequency and A is amplitude .

ω = √ ( k / m )

= √ (170 / 1.2 )

= 11.90 rad /s

amplitude A = .045 m

velocity at middle point ( maximum velocity ) = 11.9 x .045 m /s

= .5355 m /s

At middle point , no force acts so we can apply law of conservation of momentum

m₁ v₁ = ( m₁ + m₂ ) v

1.2 x .5355 = ( 1.2 + .48 ) x v

v = .3825 m /s

= 38.25 cm /s

Let new amplitude be A₁ .

1/2 m v² = 1/2 k A₁²

( 1.2 + .48 ) x v² = 170 x A₁²

( 1.2 + .48 ) x .3825² = 170 x A₁²

A₁ = .0379 m

New amplitude is .0379 m

7 0

3 years ago

.Need and actual answer not a guess

cricket20 [7]

Answer:

it's C (this is not a guess)

8 0

2 years ago

Read 2 more answers

Determine e when I = 0.50 A and R = 12 W.

sammy [17]

Answer:

The correct answer is "24 V".

Explanation:

The given values are:

Current,

I = 0.50 A

Resistance,

R = 12 W

As we know,

⇒ $I = 0.5\times (\frac{E}{2R})$

On substituting the given values, we get

⇒ $0.5= (\frac{E}{4\times 12} )$

⇒ $0.5= (\frac{E}{48} )$

⇒ $E=24 \ V$

7 0

3 years ago